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motikmotik
3 years ago
5

What are geometric isomers?

Chemistry
1 answer:
irina [24]3 years ago
3 0
<span>C. compounds that have the same atoms arranged in the same order, but with different three-dimensional orientations.</span>
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Choose the letter of the choice that best completes the statement or answers the question. Elements in the same group have the s
pav-90 [236]
Elements in the same group have D. Same number of valence electrons.
6 0
3 years ago
Read 2 more answers
You mix 145 grams of water with 200 grams of ethanol to make a solution. What is the solute and what is the solvent?
hodyreva [135]

The greater amount is the solvent and the lesser amount is the solute.

Hence ethanol(200g) which is the greater amount is the solvent here.

And water (145g) which is lesser is the solute here.

7 0
2 years ago
Sugar when dissolved into water, propose whether the compound forms atoms, molecules or lattices. Justify you answer
kirza4 [7]

Answer:

atoms

Explanation:

for sugar to dissolve in water hydaration must be equal to or greater than the lattice energy or molecular forces so when the molecular forces breaks new atoms are formed for recombination in new compound

6 0
3 years ago
What would the volume of gas be at 150 c if it had a volume of 693 ml at 45 c​
marissa [1.9K]

Answer:

\boxed{\text{922 mL}}

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = 693 mL; T₁ =  45 °C

V₂ = ?;           T₂ = 150 °C

Calculations:

(a) Convert temperature to kelvins

T₁ = (  45 + 273.15) = 318.15 K

T₂ = (150 + 273.15) = 423.15 K

(b) Calculate the volume

\dfrac{ 693}{318.15} = \dfrac{ V_{2}}{423.15}\\\\2.178 = \dfrac{ V_{2}}{423.15}\\\\V_{2} = 2.178 \times 423.15 = \boxed{\textbf{922 mL}}

5 0
3 years ago
We have an aqueous solution that contains 35% (by mass) of a hypothetical solute Z. The formula weight of the solute Z is 118 g/
Allisa [31]

Answer:

4.15 M

Explanation:

In order to find the molarity of a stock solution of Z, we use the formula;

Co = 10pd/M

where;

p = percentage by mass of Z

d = density of Z

M= molar mass of Z

Substituting values;

Co= 10 * 35 * 1.4/118

C0= 4.15 M

6 0
2 years ago
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