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3 years ago

The animal that is hunted and consumed is considered the

Physics

2 answers:

pashok25 [27]3 years ago

5 0

Predator? like they hunt their prey

KatRina [158]3 years ago

4 0

The animal that is hunted and consumed is considered the prey

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How would this sentence best be punctuated? She was a success

svetlana [45]

Answer:

She was a success.

i don't think commas are necessary because it's not a compound or complicated sentence.

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3 years ago

Write multiples and sub-multiples of second

gogolik [260]

Explanation:

Submultiples Multiples

Value SI symbol Name

10−1 s ds decasecond

10−2 s cs hectosecond

10−3 s ms kilosecond

I want brainliest plz!!!!!

3 0

2 years ago

Read 2 more answers

A particle with a charge of +4.20nC is in a uniform electric field E⃗ directed to the left. It is released from rest and moves t

Morgarella [4.7K]

Answer:

(A). The work done is $1.50\times10^{-6}\ J$ .

(B). The potential of the starting point with respect to the endpoint is 357.14 V.

(C). The magnitude of E is 5952.38 N/C.

Explanation:

Given that,

Charge = 4.20 nC

Distance = 6.00 cm

Kinetic energy $K.E=1.50\times10^{-6}\ J$

The particle start from rest.

So, the initial kinetic energy i zero.

(A). We need to calculate the work by the electric force

Using formula of work done

$W = \Delta K.E$

$W=K.E_{f}-K.E_{i}$

Put the value into the formula

$W= 1.50\times10^{-6}-0$

$W=1.50\times10^{-6}\ J$

The work done is $1.50\times10^{-6}\ J$ .

(B). We need to calculate the potential of the starting point with respect to the endpoint

We know that.

Change in potential energy = change in kinetic energy

$\Delta P.E=\Delta K.E$

So, $U = 1.50\times10^{-6}$

Using formula of potential

$V=\dfrac{U}{q}$

Put the value into the formula

$V=\dfrac{1.50\times10^{-6}}{4.20\times10^{-9}}$

$V=357.14\ V$

The potential of the starting point with respect to the endpoint is 357.14 V.

(C). We need to calculate the magnitude of E

Using formula of work done

$W=F\times r$ ....(I)

Using formula of force

$F=qE$

Put the value in the equation (I)

$W=qE\times r$

$E=\dfrac{W}{q\times r}$

Put the value into the formula

$E=\dfrac{1.50\times10^{-6}}{4.20\times10^{-9}\times6.00\times10^{-2}}$

$E=5952.38\ N/C$

The magnitude of E is 5952.38 N/C.

Hence, This is the required solution.

7 0

3 years ago

Select the correct answer.

MariettaO [177]

Answer:

can't explain but is correct

7 0

3 years ago

The relationship between two quantities that increase or decrease together is called ___

12345 [234]

The relationship between two quantities that increase or decrease together is called directly proportional.

It is a directly proportional relationship because being directly proportional means that if one increases so does the other, and if one goes down so does the other.

3 0

3 years ago