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arlik [135]
3 years ago
15

A(n) 59 kg astronaut becomes separated from

Physics
1 answer:
pantera1 [17]3 years ago
5 0

Answer:

5. 7.452 min

Explanation:

Momentum is conserved, so:

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

0 = (0.695 kg) (-12 m/s) + (59 kg) v

v = 0.1414 m/s

She is 63.2 m away, so the time it takes to reach the shuttle is:

t = 63.2 m / 0.1414 m/s

t = 447.1 s

t = 7.452 min

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Suppose you run into a wall at 4.5 meters per second (about 10 mph). Let's say the wall brings you to a complete stop in 0.5 sec
STatiana [176]

Answer with Explanation:

We are given that

Initial velocity,u=4.5 m/s

Time=t =0.5 s

Final velocity=v=0m/s

We have to find the deceleration and estimate the force exerted by wall on you.

We know that

Acceleration=\frac{v-u}{t}

Using the formula

Acceleration=a=\frac{0-4.5}{0.5}

deceleration=a=-9m/s^2

We know that

Force =ma

Using the formula and suppose mass  of my body=m=40 kg

The force exerted by wall on you

Force=40\times (9)=360N

3 0
3 years ago
A Nichrome wire 44 cm long and 0.30 mm in diameter is connected to a 3.1 V flashlight battery. What is the electric field inside
Alexeev081 [22]

Answer:

7.05 Volts/m

Explanation:

L = length of the Nichrome wire = 44 cm = 0.44 m

V = Potential difference across the end of the wire = battery voltage = 3.1 Volts

E = magnitude of electric field inside the wire

Magnitude of electric field inside the wire is given as

E = \frac{V}{L}

Inserting the values

E = \frac{3.1}{0.44}

E = 7.05 Volts/m

4 0
3 years ago
Can you please help me with this question
yaroslaw [1]

Um it's so dark here I can't find the question lol...

4 0
2 years ago
Find the distance travelled when the initial angular velocity is 3 rad/s, the final angular velocity is 25 rad/s and the time of
Llana [10]

Answer:

Please find attached pdf

Explanation:

Download pdf
5 0
3 years ago
Mary is at the top of a 25 m steep slide. She is then pushed and starts accelerating at a rate of 4.3 m/s"2. How long will it ta
Gemiola [76]

<u>Answer</u>

3.4 s


<u>Explanation</u>

The question can be solve by using the 2nd Newton's law of motion.

s = ut + 1/2at²

Before she is pushed, the  initial velocity is zero.

u = 0

Now the equation becomes

s = 0 + 1/2at²

s = 1/2at²

25 = 1/2 × 4.3 × t²

50 = 4.3t²

t² = 50/4.3

  = 11.628

t = √11.628

   = 3.4 s

8 0
3 years ago
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