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ANTONII [103]
4 years ago
9

True or False? a globular cluster is a group of older stars that are clustered together.

Physics
2 answers:
horsena [70]4 years ago
4 0
I would have to say the answer it false
Effectus [21]4 years ago
3 0
<span><u><em>This statement is True.</em></u>
</span>
<span><u><em>A globular cluster is a collection of stars that orbits a galactic core as a satellite.</em></u>
<u><em>Hope u happy times!</em></u>
</span>
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Does water have mass? How do you know?
Bess [88]

every thing on this earth has it,s own mass

8 0
4 years ago
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In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasin
GuDViN [60]

Answer:

The velocity is v_b = 20.17 \ m/s

Explanation:

From the question we are told that

   The mass of the ball is  m = 0.245 \ kg

   The radius is  r =  59.8 \  cm  =  0.598 \ m

   The force is  F =  30.9 \ N

   The speed of the ball is  v = 16.0 \ m/s.

Generally the kinetic energy at the top of the circle is mathematically represented as

    K_t  =  \frac{1}{2} *  m  *  v^2

=> K_t  =  \frac{1}{2} *  0.245   *  16.0 ^2  

=> K_t  =  31.36 \ J  

Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

       W =  F *  d

Here  d is the length of  a semi - circular arc which is mathematically represented as

       d =  \pi * r

So

      W =  30.9 *  0.598

      W = 18.48 \ J

Generally the kinetic energy at the bottom is mathematically represented as

      K_b  =  \frac{1}{2} *  m *  v_b^2

=>    K_b  =  \frac{1}{2} *  0.245  *  v_b^2

=>   K_b  =  0.1225  *  v_b^2

From the law of energy conservation

     K_t +  W  =K_b

=>    31.36+  18.48 = 0.1225  *  v_b^2

=>    v_b = 20.17 \ m/s

3 0
3 years ago
A kind of tempory magnet​
netineya [11]

Answer:

Common temporary magnets include nails and paperclips, which can be picked up or moved by a strong magnet. Another type of temporary magnet is an electromagnet which only retains magnetism when an electrical current is running through it.

Explanation:

8 0
3 years ago
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A beam of light with a frequency range from 3.01 × 10 14 Hz to 6.10 × 10 14 Hz is incident on a metal surface. If the work funct
Sever21 [200]

Answer:

The maximum kinetic energy of the photoelectrons ejected from the surface is 5.22×10^-20 J.

Explanation:

let h = 6.626×10^-34 J×s be the planck constant.

let f be the frequency of light.

let Ф = 2.20×1.60×10^-19 = 3.52×10^-19 J be the work function.

then, the relationship  between the kinetic energy of photoelectrons K, the energy provided by the light E and the work function of the material is given by:

K = h×f - Ф

  = (6.626×10^-34)×(6.10×10^14) - 3.52×10^-19

  = 5.22×10^-20 J

Therefore, the maximum kinetic energy of the photoelectrons ejected from the surface is 5.22×10^-20 J.

5 0
3 years ago
A 25.0-kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic frictio
Leni [432]

Answer:

Explanation:

a ) When the box starts to slip

static friction = mg sinα

mg cosα x μ =  mg sinα (  μ is coefficient of static friction )

Tanα =  μ  = .35

α  = 19.2°

b ) Once box starts moving , kinetic friction will start applying on it

kinetic friction = mg cos19.2 x .25

= 2.31m

net force downward = mgsin19.2 - mgcos19.2 x .25

= m ( 3.22 - 2.31 )

= .91 m

acceleration downward ( a )   = .91 m / s²

c )

v² = u² + 2 a s

= 0 + 2 x .91 x 5

= 9.1

v = 3 m / s

3 0
4 years ago
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