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yarga [219]
3 years ago
5

Problem page a cyclist traveled 20 kilometers per hour faster than an in-line skater. in the time it took the cyclist to travel

80 kilometers, the skater had gone 30 kilometers. find the speed of the skater.
Physics
1 answer:
RideAnS [48]3 years ago
3 0
<span>Answer: skater x km/h cyclist 20 faster x + 20 km/h skater 30 km cyclist 80 km skater time = cyclist time t=d/r 30 / x = 80 /( x + 20 cross multiply 30 ( x + 20 ) = 80 x 30 x + 600 = 80 x 30 x - 80 x = -600 -50 x = -600 / -50 x = 12 km/h 12 km/h skater</span>
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8 0
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Answer:

d = 90 ft

Explanation:

As we know that after each bounce it reaches to 4/5 times of initial height

so we can say

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d = h + 2(\frac{4}{5}h) + 2(\frac{4}{5})^2h + 2(\frac{4}{5})^3h........

here we know that

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d = 10 + 2(\frac{4}{5}(10))(\frac{1}{1 - \frac{4}{5}})

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8 0
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Explanation:

hoped this helped have a good day :)

5 0
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energy. It will not disrupt the picture developing process by overexposing too much light on the film.

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