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Degger [83]
4 years ago
10

Explain how Earth, the moon, and the Sun move relative to one another.

Physics
1 answer:
Annette [7]4 years ago
6 0

If you stand on top of the sun, and one foot off of the surface so that you don't rotate with the sun, while wearing the calendar watch you bought on Earth . . .

. . . the Sun rotates under your feet about once a month;

. . . you see the Earth revolving around you once a year;

. . . you see the Moon revolving around you once a year, and ALSO wiggling slightly in and out, slightly nearer and farther from you.  When it's nearer, it's slightly nearer to you than the Earth is.  When it's farther, it's slightly farther from you than the Earth is.  About half of the wiggle, it's slightly to the left of the Earth, ahead of the Earth in its orbit.  The other half, it's slightly to the right of the Earth, behind the Earth in its orbit.  The Moon goes through a complete one of these near-and-far wiggles every 27.3 days.

If you stand on top of the Earth, and one foot off the ground so that you don't rotate with the Earth . . .    

. . .  the Earth rotates under your feet about once every 24 hours;

. . .  you see the Sun revolving around you once a year;

. . .  you see the Moon revolving around you once every 27.3 days.  The Moon is also rotating, but it takes exactly the same 27.3 days to rotate once, so it ends up keeping the same side facing you all the time, and you can never see anything on the other side.

If you stand on top of the Moon, one foot off of the surface so that you don't rotate with the Moon, while wearing the same calendar watch that you bought on Earth . . .

. . . the Moon rotates under your feet, about once every 27.3 days;

. . . you see the Earth revolving around you at exactly the same rate, about once every 27.3 days, so that if you look down at the Moon beneath your feet, you notice that the same side of it is always facing the Earth, and the other side of the Moon can never see the Earth.

. . . you see the Sun revolving around you once a year.      

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Which form of the energy is used to generate electrical energy in a tidal power station
Alla [95]

Tidal energy is the form of energy used to generate electrical energy.

7 0
3 years ago
Since alcohol evaporate faster than water if I leave a beer out will it become alcohol free before completely evaporating?
Bas_tet [7]
I dont think so since the alcohol is still mixed into the water so I think they will evaporate at the same time.
3 0
3 years ago
A car is initially moving at 35 km/h along a straight highway. To pass another car, it speeds up to 135 km/h in 10.5 seconds at
Aleks04 [339]
Acceleration = (velocity final-velocity initial)/ time
where
velocity final = 135 km/hr x 1 hr /3600 s x 1000m/1km
                     = 37.5 m/s
velocity initial = 35 km/hr x  1hr /3600 s x 1000 m/1 km
                      =  9.72 m/s
a) acceleration = 2.646 m/s^2
b) acceleration in g units  = (2.646m/s^2)/(9.8m/s^2)
                                              = 0.27 units

6 0
4 years ago
5
Ronch [10]

Answer:

Current in a parallel circuit = 0.61 amps (Approx)

Explanation:

Given:

Voltage V = 6 volt

Two resistors = 17.2 , 22.4 in parallel circuit

Find:

Current in a parallel circuit

Computation:

1/R = 1/r1 + 1 / r2

1/R = 1/17.2 + 1 / 22.4

R = 9.73 ohms (Approx)

Current in a parallel circuit = V / R

Current in a parallel circuit = 6 / 9.73

Current in a parallel circuit = 0.61 amps (Approx)

4 0
3 years ago
You find a bag labeled "10 kg of lead-210". Its contents now weigh 1.25 kg. How many half-life periods have there been since the
zlopas [31]

Answer : The number of half-life periods will be, 3

Explanation :  Given,

Initial amount of lead = 10 kg

Amount of lead after decay = 1.25 kg

Half-life = 22 years

Formula used :

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives

a_o = Initial amount of the reactant

n = number of half lives

t_{1/2} = half-life

Now put all the given values in the above formula, we get:

1.25=\frac{10}{2^n}

2^n=8

2^n=2^3

n=3

Thus, the number of half-life periods will be, 3

5 0
4 years ago
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