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charle [14.2K]
4 years ago
11

an ant weighing 200 N and wearing platform heels with a total area of 7 square centimeters would exert how much pressure?​

Physics
1 answer:
iVinArrow [24]4 years ago
7 0

The pressure exerted is 2.86\cdot 10^5 Pa

Explanation:

The pressure exerted by a force on a surface is given by

p=\frac{F}{A}

where

p is the pressure

F is the magnitude of the force

A is the area of the surface

In this problem, we have:

F = 200 N is the force exerted (the weight of the ant)

A=7 cm^2 = 7\cdot 10^{-4} m^2 is the area

Therefore, the pressure exerted is:

p=\frac{200}{7\cdot 10^{-4}}=2.86\cdot 10^5 Pa

Learn more about pressure:

brainly.com/question/4868239

brainly.com/question/2438000

#LearnwithBrainly

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Can cars stop on a dime? Calculate the acceleration of a 1400 kg car if it can stop from 35 km/h on a dime (diameter= 1.7 cm) ho
Deffense [45]

Answer:

The acceleration of the cart is 283.54g

Explanation:

It is given that,

Initial speed of the car, u = 35 km/h = 9.72 m/s

Finally, it stops, v = 0

Diameter of the dime, d = 1.7 cm

Let a is the acceleration of the car. Using third equation of motion to find it as :

v^2-u^2=2ad

-u^2=2ad

a=\dfrac{-u^2}{2d}

a=-\dfrac{(9.72)^2}{2\times 1.7\times 10^{-2}}

a=-2778.77\ m/s^2

So, the acceleration of the car is 2778.77\ m/s^2 and it is decelerating.

Since, g=9.8\ m/s^2

So, a=\dfrac{2778.77}{9.8}=283.54\ g

So, the acceleration of the cart is 283.54g. Hence, this is the required solution.

6 0
3 years ago
The velocity of sound in air at 300C is approximately :
kumpel [21]

The velocity of sound in at 300C is 511.3 m/s.

Explanation:

The equation that gives the speed of sound in ar as a function of the air temperature is the following:

v=(331.3+0.6T) m/s

where

T is the temperature of the air, measured in Celsius degrees

In this problem, we want to find the speed of sound in ar for a temperature of

T=300^{\circ}C

Substituting into the equation, we find:

v=331.3 + 0.6(300)=511.3 m/s

So, the velocity of sound in at 300C is 511.3 m/s.

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brainly.com/question/4899681

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6 0
3 years ago
A 2600-m-high mountain is located on the equator. how much faster does a climber on top of the mountain move than a surfer at a
puteri [66]

The climber move 0.19 m/s  faster than surfer on the nearby beach.

Since both the person are on the earth, and moves with the constant angular velocity of earth, however there linear velocity is different.

Number of seconds in a day, t=24*60*60=86400 sec

The linear speed on the beach is calculated as

V1=\frac{2πr}{t}

Here, t is the time

Plugging the values in the above equation

V1=\frac{2π*6.4*10^6}{86400}=465.421 m/s

Velocity on the mountain is calculated as

V2=\frac{2π(r+h)}{t}

Plugging the values in the above equation

V2=\frac{2π(6.4*10^6+2600}{86400}=465.61 m/s

Therefore person on the mountain moves faster than the person on the beach by 465.61-465.421=0.19 m/s

5 0
3 years ago
SOMEONE PLEASE HELP!!!! <br> Select the correct answer. Which planet is planet A
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Saturn is the answer 

4 0
4 years ago
A truck travels to and from a stone quarry that is located 2.5 km to the east. What is the total distance traveled by the truck?
scoray [572]

Answer:

5 km

0

Explanation:

The question says the truck travelled to and fro from the stone quarry.

When going to the stone quarry, the distance was 2.5 km to the east.

On returning, the distance back is also 2.5km

Therefore total distance travelled is 2.5km + 2.5km

= 5km

The displacement 8s dependent on what is the initial and also the final position. The initial and the final position are one and the same thing. Because the truck starts and goes back to the same position, the displacement is zero.

5 0
3 years ago
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