Answer:
The acceleration of the cart is 283.54g
Explanation:
It is given that,
Initial speed of the car, u = 35 km/h = 9.72 m/s
Finally, it stops, v = 0
Diameter of the dime, d = 1.7 cm
Let a is the acceleration of the car. Using third equation of motion to find it as :





So, the acceleration of the car is
and it is decelerating.
Since, 
So, 
So, the acceleration of the cart is 283.54g. Hence, this is the required solution.
The velocity of sound in at 300C is 511.3 m/s.
Explanation:
The equation that gives the speed of sound in ar as a function of the air temperature is the following:

where
T is the temperature of the air, measured in Celsius degrees
In this problem, we want to find the speed of sound in ar for a temperature of

Substituting into the equation, we find:

So, the velocity of sound in at 300C is 511.3 m/s.
Learn more about sound waves:
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The climber move 0.19 m/s faster than surfer on the nearby beach.
Since both the person are on the earth, and moves with the constant angular velocity of earth, however there linear velocity is different.
Number of seconds in a day, t=24*60*60=86400 sec
The linear speed on the beach is calculated as
V1=
Here, t is the time
Plugging the values in the above equation
V1=
=465.421 m/s
Velocity on the mountain is calculated as
V2=
Plugging the values in the above equation
V2=
=465.61 m/s
Therefore person on the mountain moves faster than the person on the beach by 465.61-465.421=0.19 m/s
Answer:
5 km
0
Explanation:
The question says the truck travelled to and fro from the stone quarry.
When going to the stone quarry, the distance was 2.5 km to the east.
On returning, the distance back is also 2.5km
Therefore total distance travelled is 2.5km + 2.5km
= 5km
The displacement 8s dependent on what is the initial and also the final position. The initial and the final position are one and the same thing. Because the truck starts and goes back to the same position, the displacement is zero.