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Slav-nsk [51]
3 years ago
8

Which Roman numeral is equivalent to the number below?

Mathematics
1 answer:
mafiozo [28]3 years ago
5 0
I believe LX is the answer.
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Can somebody help me with thiss??
Strike441 [17]
I guess it’s options (d)
8 0
3 years ago
A study of more than 3,000 toco toucans found that their weights were approximately Normally distributed, with a mean
ANTONII [103]

Using the normal distribution, it is found that the correct option is:

  • P(Y< 16) = 0.041. About 4.1% of all toco toucans weigh less than 16 ounces

In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • Mean of 20 ounces, hence \mu = 20.
  • Standard deviation of 2.3 ounces, hence \sigma = 2.3

P(Y < 16) is the <u>p-value of Z when X = 16</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{16 - 20}{2.3}

Z = -1.74

Z = -1.74 has a p-value of 0.041.

This is valid for the entire population, hence, the correct interpretation is:

  • P(Y< 16) = 0.041. About 4.1% of all toco toucans weigh less than 16 ounces

A similar problem is given at brainly.com/question/24663213

4 0
2 years ago
Help with 30 please. thanks.​
Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

\displaystyle  y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}

And we want to show that:

\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}

Instead of differentiating directly, we can first square both sides:

\displaystyle y^2 = 3e^{2x} -4x + 1

We can find the first derivative through implicit differentiation:

\displaystyle 2y \frac{dy}{dx}  = 6e^{2x} -4

Hence:

\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}

And we can find the second derivative by using the quotient rule:

\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}

Substitute:

\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}

Simplify:

\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}

Combine fractions:

\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}

Simplify:

\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}

Simplify:

6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}

Q.E.D.

6 0
2 years ago
Can you help me asap please
snow_tiger [21]

Answer:

-2, 4. -2 is x and 4 is y

Step-by-step explanation:

hope this helps!

3 0
3 years ago
PLEASE ANSWER ASAP<br> ..............................................
Tema [17]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
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