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gogolik [260]
3 years ago
9

Why would it be important for a scientist to understand HOW an element would react with another element?

Chemistry
2 answers:
Nikolay [14]3 years ago
6 0
Shorter answer would be to see whether they react or not. That might not be right it's just my assumption
Eddi Din [679]3 years ago
3 0
Sounds good, but would do little to explain why lithium, with 3 electrons, is more reactive than Helium with 2,  or why Caesium is more reactive than Sodium, although it clearly has far more electrons with which to shield its nucleus.

Hydrogen is unusual in having a fairly exposed nucleus, but chemistry is not very much about the nucleus, it is about the way the electrons themselves interact.  As Lightarrow suggests, it does help if you know the quantum behaviour of electrons in an atom (which I do not claim to know), but it basically boils down to electrons preferring some configurations over others.

At the simplest, the comparison between hydrogen and helium – it is not really to do with the nucleus, it is more to do with electrons liking to be in pairs.  Electrons have (like most common particles) two possible spin states, and they are more stable when an electron in one spin state is paired with an electron in the opposite spin state.  When two hydrogen atoms meet, the electrons each one of them hold can be shared between them, forming a more stable pair of electrons, and thus binding the two atoms together.

All of the group 1 atoms (hydrogen, lithium, sodium, potassium, caesium; all share the characteristic that they have an odd number of electrons, and that one of those electrons is relatively unstable.  The reason that the heavier atoms are more reactive is quite contrary to the argument that Lightarrow put forward – it is not because of a stronger electrical reaction with the nucleus, but because of the larger number of electrons in the bigger atoms, they are actually more weakly attached to their own nucleus, and so more readily interact with the electrons of other atoms.

Another, even more stable configuration for the electrons around an atom requires 8 electrons.  This gives the noble gases (apart from Helium) their stability, but it also gives atoms like chlorine and fluorine their reactivity.  Atoms like those of chlorine and fluorine are only one electron short of having a group 8 electrons available to them, and so will readily snatch an electron from another atom (particularly if it is an atom that has a single loose electron, such as sodium or caesium) in order to make up that group of 8 electrons.

The above explanation is very crude, and really does need a proper understanding of the quantum states of electrons to give a better quantitative answer (it is probably the kind of answer that might have been acceptable in the 1920s or 1930s – the Bohr orbital model of the atom, but has now been superseded by better explanations of what goes on amongst the electrons of an atom).



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Given the reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 607.3 kJ XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = + 356.9 kJ wh
tresset_1 [31]

Answer:

The answer to your question is ΔH = -964.2 kJ

Explanation:

Data

Reaction 1        X  +  12O₂  ⇒  XO            ΔH = -607.3 kJ

Reaction 2       XCO₃  ⇒  XO  +  CO₂      ΔH = 356.9 kJ

ΔH for  Reaction 3   X  +  12O₂ +  CO₂  ⇒  XCO₃

Process

1.- Write the Reaction 1 the same      

2.- Invert the order of reaction 2, and change the sign of the Enthalpy

Reaction 1        X  +  12O₂  ⇒  XO            ΔH = -607.3 kJ

Reaction 2       XO  +  CO₂ ⇒ XCO₃       ΔH = - 356.9 kJ

3.- Sum up the reactions

                       X + 12O₂ + XO + CO₂ ⇒  XO + XCO₃

4.- Simplify

                       X + 12O₂ + CO₂ ⇒  XCO₃  ΔH = -964.2 kJ

7 0
3 years ago
Write the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by each:
Sladkaya [172]

Answer:

Part A:

Charge is P^{3-}

Configuration is 1s^2 2s^22p^63s^23p^6

Part B:

Charge is Mg^{2+}

Configuration is 1s^2 2s^22p^6

Part C:

Charge is Se^{2-}

Configuration is 1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6

Explanation:

Monatomic ions:

These ions consist of only one atom. If they have more than one atom then they are poly atomic ions.

Examples of Mono Atomic ions: Na^+, Cl^-, Ca^2^+

Part A:

For P:

Phosphorous (P) has 15 electrons so it require 3 more electrons to stabilize itself.

Charge is P^{3-}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^63s^23p^6

Part B:

For Mg:

Magnesium (Mg) has 12 electrons so it requires 2 electrons to lose to achieve stable configuration.

Charge is Mg^{2+}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^6

Part C:

For Se:

Selenium (Se) has 34 electrons and requires two electrons to be stable.

Charge is Se^{2-}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6

8 0
3 years ago
Help me
Valentin [98]

Answer:

South American

Explanation:

When you look at a map of plates, only South American forms a boundary with the African plate out of those specific plates

6 0
3 years ago
Read 2 more answers
Which piece of evidence did Alfred Wegener's original theory of continental drift have access to?
alukav5142 [94]

Answer:

the fossil clues and rock clues and the coastlines

Explanation:

hope this helps

5 0
3 years ago
The pressure inside a compressed gas cylinder is 144 atm at 48°C. What will the pressure inside the cylinder be after it is cool
Andrews [41]
<h3>Answer:</h3>

134 atm

<h3>Explanation:</h3>
  • Based on the pressure law, the pressure of a gas varies directly proportionally to the absolute temperature at a constant volume.
  • Therefore; we are going to use the equation;

\frac{P1}{T1}=\frac{P2}{T2}

In this case;

Initial pressure, P1 = 144 atm

Initial temperature, T1 (48°C) = 321 K

Final temperature, T2 (25°C) = 298 K

We need to find the final pressure,

Therefore;

P2 = (P1/T1)T2

    = (144/321)× 298 K

    = 133.68 atm

   = 134 atm

Therefore, the new pressure will be 134 atm.

5 0
4 years ago
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