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iren [92.7K]
3 years ago
9

What are the Respiration effects on the pH?

Chemistry
1 answer:
WITCHER [35]3 years ago
3 0
Our blood have a pH around the 7.0, when we hold the breath our cells still breathing, and the release CO_2, this compound react with water (hydrolysis).

H_2O+CO_2\leftrightharpoons H_2CO_3

This compound formed by this reaction is acid, carbonic acid.

Them the pH will get lower them normal, and our buld send an action to our body, and this reaction will be the <span>breathing.</span>
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How many moles of aspartame are present in 1.00 mg of aspartame?
Diano4ka-milaya [45]

Answer:- There are 3.40*10^-^6 moles.

Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is C_1_4H_1_8N_2O_5 and it's molar mass is 294.31 grams per mole.

mg are converted to grams and then the grams are converted to moles as:

1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})

= 3.40*10^-^6 moles of aspartame

So, there would be 3.40*10^-^6 moles of aspartame in 1.00 mg of it.

3 0
3 years ago
2. This graph shows the energy involved in a reaction involving two molecules. Describe what is happening or what the state of t
blagie [28]
If you think of it endothermic is when there is energy needed for the reaction to occur and exothermic is when the reaction releases energy
6 0
3 years ago
3. All the deer in Horry County represent which of the following?
klemol [59]

Answer:

community

Explanation:

8 0
2 years ago
Read 2 more answers
An air compressor takes atmospheric air (think about what pressure it is at) and pressures it up to 68 (psig). In the process, i
Aleks [24]

Answer:

5.19 m³  

Explanation:

Data Given:

initial Pressure P1 = atmospheric pressure

Reported atmospheric pressure =  14.696 psi

Final pressures P2 =  68 psi

initial Temperature T1 =  26 °C

final Temperature T2 =  48 °C

initial Volume V1= 13 m³

final Volume V2 = ?

Solution:

Formula will be used

                    P1 V1 / T1 = P2 V2 / T2

To calculate volume rearrange the above formula

                   V2 = (P1 V1) T2 / T1 P2 . . . . . . . .(1)

put values in equation 1

                  V2 = (14.696 psi x 13 m³) 48 °C / 26 °C x 68 psi

                  V2 = (191.05 psi m³) 48 °C / 1768 °C psi

                  V2 = (9170.3  psi m³ °C / 1768 °C psi

                  V2 = 5.19 m³

So, final volume is 5.19 m³                

7 0
3 years ago
In boyle's law, the initial volume of a gas is 120 ml at 256 kpa. what will be the volume if the pressure increases to 385 kpa?
Vinil7 [7]
<h3>Answer:</h3>

79.8 ml

<h3>Explanation:</h3>

Boyle's law describes the relationship between pressure and volume when the temperature is constant. For this question, I will be rounding to significant figures.

Boyle's Formula

When describing the relationship between pressure and volume, the formula \displaystyle P_{1} V_{1}= P_{2} V_{2}. In this formula, P_{1}V_{1} is the initial pressure and volume. On the other side, P_{2} V_{2} is final pressure and volume. So, to find a missing variable you must plug in the values you are given.

Final Volume

Remember when solving this question to remain constant in your units. When we plug in the values we know we are given:

  • 256kPa*120mL=385kPa*V_{2} mL

Now, we can multiply the left side

  • 30720kPa*mL=385kPa*V_{2} mL

Finally, we can divide by 385 to isolate the final volume

  • 79.8mL=V_{2}

This gives the final volume of 79.8mL.

7 0
2 years ago
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