Answer:- There are
moles.
Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is
and it's molar mass is 294.31 grams per mole.
mg are converted to grams and then the grams are converted to moles as:

=
moles of aspartame
So, there would be
moles of aspartame in 1.00 mg of it.
If you think of it endothermic is when there is energy needed for the reaction to occur and exothermic is when the reaction releases energy
Answer:
5.19 m³
Explanation:
Data Given:
initial Pressure P1 = atmospheric pressure
Reported atmospheric pressure = 14.696 psi
Final pressures P2 = 68 psi
initial Temperature T1 = 26 °C
final Temperature T2 = 48 °C
initial Volume V1= 13 m³
final Volume V2 = ?
Solution:
Formula will be used
P1 V1 / T1 = P2 V2 / T2
To calculate volume rearrange the above formula
V2 = (P1 V1) T2 / T1 P2 . . . . . . . .(1)
put values in equation 1
V2 = (14.696 psi x 13 m³) 48 °C / 26 °C x 68 psi
V2 = (191.05 psi m³) 48 °C / 1768 °C psi
V2 = (9170.3 psi m³ °C / 1768 °C psi
V2 = 5.19 m³
So, final volume is 5.19 m³
<h3>
Answer:</h3>
79.8 ml
<h3>
Explanation:</h3>
Boyle's law describes the relationship between pressure and volume when the temperature is constant. For this question, I will be rounding to significant figures.
Boyle's Formula
When describing the relationship between pressure and volume, the formula
. In this formula,
is the initial pressure and volume. On the other side,
is final pressure and volume. So, to find a missing variable you must plug in the values you are given.
Final Volume
Remember when solving this question to remain constant in your units. When we plug in the values we know we are given:
Now, we can multiply the left side
Finally, we can divide by 385 to isolate the final volume
This gives the final volume of 79.8mL.