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Anastaziya [24]
3 years ago
13

What is the pH of a solution made by mixing equal volumes of 1 M sodium acetate and 1 M acetic acid? (The pK of acetic acid is 4

.76.)
a) 1
b) 3.76
c) 4.76
d) 5.76
Chemistry
1 answer:
Solnce55 [7]3 years ago
3 0

Answer:

The pH is 4.76 (option C)

Explanation:

pH of a solution = TO BE DETERMNED

[sodium acetate] = 1M   ;   [acetic acid] = 1M

K = [H+] [A-] / [HA] 

K = [H+] [1] / [1] 

K = H  

pH = pK

⇒ now pH is equal to pK

⇒ The value of pK is given which is 4.76

⇒ This means the value of the pH is also 4.76

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The standard cell potential of the following galvanic cell is 1.562 V at 298 K. Zn(s) | Zn2+(aq) || Ag+(aq) | Ag(s) What is the
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Answer:

E = 1.602v

Explanation:

Use the Nernst Equation => E(non-std) = E⁰(std) – (0.0592/n)logQc …

             Zn⁰(s) => Zn⁺²(aq) + 2 eˉ

2Ag⁺(aq) + 2eˉ=> 2Ag⁰(s)          

_____________________________

Zn⁰(s) + 2Ag⁺(aq) => Zn⁺²(aq) + 2Ag(s)

Given E⁰ = 1.562v

Qc = [Zn⁺²(aq)]/[Ag⁺]² = (1 x 10ˉ³)/(0.150)² = 0.044

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4 0
3 years ago
Read 2 more answers
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Nezavi [6.7K]
A circuit breaker must be replaced after too much current flowing through it causing it to melt.
6 0
2 years ago
The edge length of the unit cell of KCl (NaCl-like structure, FCC) is 6.28 Å. Assuming anion-cation contact along the cell edge,
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Answer:

1.33 Å

Explanation:

Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å

Also,

For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.

Thus,

\frac {r^+}{r^-}=0.731 .................1

Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.

Thus,

r^++r^-=\frac {a}{2}  ...................2

Given that:

Cl^-\ (r^-) = 1.82\ \dot{A}

To find,

K^+\ (r^+) = ? \dot{A}

Using 1 and 2 , we get:

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<u>Size of the potassium ion = 1.33 Å</u>

4 0
3 years ago
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icang [17]

Answer:

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Explanation:

The whole question can be found in the file attached.

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