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alexandr1967 [171]
3 years ago
9

Suppose that a constant force is applied to an object. newton's second law of motion states that the acceleration of the object

varies inversely with its mass. a certain force acting upon an object with mass 3 kg produces an acceleration of 15 /ms2 . if the same force acts upon another object whose mass is 5 kg , what would this object's acceleration be?
Physics
1 answer:
amm18123 years ago
6 0
Solve for "x"
X = speed of the 5 kg 
3/15=5/x
cross multiply 
3x=75 
because (15)(5)=(3)(x)
divide 3 in both side
X=25 
or 
A=25 m/s^2 
Hope this helps

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Through what angle in degrees does a 33 rpm record turn in 0.32 s?<br> 63°<br> 35°<br> 46°<br> 74°
Darina [25.2K]

Answer:

1 rev = 2(pi) rad  pi(rad) = 180 degrees

so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees

Explanation:

63.36 estimated to 63 so 63

6 0
2 years ago
A 4 kg bowling ball rolls at a speed of 5 m/s on the roof of a building that is 30 meters tall. What is its kinetic energy?
klasskru [66]

ans: B

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= \frac{1}{2} (4)(5^{2} )

= 50J

ps. the height will only affect its potential energy, not kinetic.

3 0
3 years ago
For a spacecraft or a molecule to leave the moon, it must reach the escape velocity (speed) of the moon, which is 2.37 km/s. The
guapka [62]

Answer:

Vrms = 291 m/s

Explanation:

The root mean square velocity or vrms is the square root of the average square velocity and is. vrms=√3RTM. Where M is equal to the molar mass of the molecule in kg/mol.

Temperature = 365 K

Root mean square velocity = ?

molar mass of oxygen = 16 g/mol.

But xygen gas (O2) is comprised of two oxygen atoms bonded together. Therefore:

   molar mass of O2 = 2 x 16

   molar mass of O2 = 32 g/mol

   Convert this to kg/mol:

   molar mass of O2 = 32 g/mol x 1 kg/1000 g

   molar mass of O2 = 3.2 x 10-2 kg/mol

Molar mass of Oxygen = 3.2 x 10-2 kg/mol

Vrms = √[3(8.3145 (kg·m2/sec2)/K·mol)(365 K)/3.2 x 10-2 kg/mol]

Vrms = 291 m/s

8 0
3 years ago
Read 2 more answers
Need help with question 1) and 2) please ASAP ??? 15 points ?
Vaselesa [24]
1- interaction between 2 objects
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3 0
3 years ago
You push a refrigerator with a force of 100 N. If you move the refrigerator a distance of 5 m while you are pushing, how much wo
ddd [48]

The work done to push the refrigerator is 500 Nm.

Explanation:

Work done is the measure of force required to move any object from one point to another. So it is calculated as the product of force and displacement.

If the force increases the work done will increase and similarly, the increase in displacement increases the work done. So to push the refrigerator work should be done on the object and not by the object.

As the force is 100 N and the displacement is 5 m then, work done can be measured as

Work = Force × Displacement

Work = 100 × 5 = 500 Nm

So the work done to push the refrigerator is 500 Nm.

7 0
3 years ago
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