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alexandr1967 [171]
3 years ago
9

Suppose that a constant force is applied to an object. newton's second law of motion states that the acceleration of the object

varies inversely with its mass. a certain force acting upon an object with mass 3 kg produces an acceleration of 15 /ms2 . if the same force acts upon another object whose mass is 5 kg , what would this object's acceleration be?
Physics
1 answer:
amm18123 years ago
6 0
Solve for "x"
X = speed of the 5 kg 
3/15=5/x
cross multiply 
3x=75 
because (15)(5)=(3)(x)
divide 3 in both side
X=25 
or 
A=25 m/s^2 
Hope this helps

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Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is λA = 622nm. The other wavelength is λ
Sergio039 [100]

Answer:

\lambda_{B}=414.67 nm

Explanation:

In this question we have given

\lambda_{A}=622nm

we have to find

\lambda_{B}=?

We know that

optical path difference for bright fringe is given as=n\lambda

Here,

n is order of fringe

and optical path difference for dark fringe is given as=(n+.5)\lambda

since the light with wavelength \lambda_{A} produces its third-order bright fringe at the same place where the light with wavelength \lambda_{B} produces its fourth dark fringe  

it means

optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe

Therefore,

3\lambda_{A}=(4+.5)\lambda_{B}...............(1)

Put value of \lambda_{A} in equation (1)

3 \times 622=(4+.5)\lambda_{B}

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