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3 years ago

What is the dimensional formula of young modulas

Physics

2 answers:

LekaFEV [45]3 years ago

6 0

Answer:

The dimensional formula of Young's modulus is [ML^-1T^-2]

natita [175]3 years ago

4 0

Answer:

G.oogle : The dimensional formula for Young’s modulus is:

A. [ML−1T−2]A. [ML−1T−2]

B. [M0LT−2]B. [M0LT−2]

C. [MLT−2]C. [MLT−2]

D. [ML2T−2]

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3 years ago

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Given:

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Explanation: to calculate the kinetic energy of a body we will use the formula as

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first, we convert velocity from mi/h into m/s.

we know that

$1\text{ mi=1609.34 m}$

and

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now plugging all the values in the above formula, we get

$\begin{gathered} K.E=\frac{1}{2}mv^2 \\ K.E=\frac{1}{2}\times1.23\text{ kg}\times(29.29\text{ m/s})^2 \\ K.E=527.61\text{ J} \end{gathered}$

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What is the elastic potential energy of a spring that is compressed a distance of 0.35 m and has a spring constant of 71.8 N/m?

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Answer:

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Explanation:

Given the following data;

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$P.E = \frac {1}{2}kx^{2}$

Substituting into the equation, we have;

$P.E = \frac {1}{2}*71.8 *(0.35)^{2}$

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<em>Therefore, the elastic potential energy of the spring is 4.398 Joules. </em>

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3 years ago

What is the dimensional formula of young modulas​

What is the dimensional formula of young modulas