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andreev551 [17]
3 years ago
13

What is the dimensional formula of young modulas​

Physics
2 answers:
LekaFEV [45]3 years ago
6 0

Answer:

The dimensional formula of Young's modulus is [ML^-1T^-2]

natita [175]3 years ago
4 0

Answer:

G.oogle : The dimensional formula for Young’s modulus is:

A. [ML−1T−2]A. [ML−1T−2]

B. [M0LT−2]B. [M0LT−2]

C. [MLT−2]C. [MLT−2]

D. [ML2T−2]

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proton is accelerated to a speed of 0.93c, what is the 1. A proton has a mass of 1.673 x 10-27 kg. If the proton is accelerated
coldgirl [10]

Answer : The correct option is, (B) 1.3\times 10^{-18}kg.m/s

Explanation : Given,

Mass of proton = 1.673\times 10^{-27}kg

Speed of proton = 0.93 c

Formula used for relativistic momentum of the proton is:

p=\frac{m_ov}{\sqrt{1-\frac{v^2}{c^2}}}

where,

p = relativistic momentum of the proton

m_o = mass of proton

v = speed of proton

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

p=\frac{(1.673\times 10^{-27}kg)\times (0.93c)}{\sqrt{1-\frac{(0.93c)^2}{c^2}}}

p=\frac{(1.55589\times 10^{-27}c)}{0.367}

p=\frac{(1.55589\times 10^{-27})\times (3\times 10^8)}{0.367}

p=1.272\times 10^{-18}kg.m/s\approx 1.3\times 10^{-18}kg.m/s

Therefore, the relativistic momentum of the proton is, 1.3\times 10^{-18}kg.m/s

5 0
3 years ago
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The 1.5-kg collar C starts from rest at A and slides with negligible friction on the fixed rod in the vertical plane. Determine
arlik [135]

Answer:

Explanation:

check attached image for figure, there is supposed to be a figure for this question containing a distance(height of collar at position A) but i will assume 0.2m or 200mm

Consider the energy equilibrium of the system

U_{A-B}=\bigtriangleup T\\\\F\cos 30°\times h_A - F\sin30°\times h_A + Wh_A=\frac{1}{2}m(v^2_B-v^2_A)\\\\v_B=\sqrt{\frac{2Fh_A(\cos 30° - \sin30°)+mgh_A}{m+v^2_A}}

Here, F is the force acting on the collar, h_A is the height of the collar at position A, m is the mass of the collar C, g is the acceleration due to gravity, v_B is the velocity of the collar at position B, and v_A is the velocity of the collar at A

Substitute 14.4N for F, 0.2m for h_A, 1.5kg for m, 9.81m/s^2 for g and 0 for v_A

v_B=\sqrt{\frac{2(14.4\times 0.2(\cos 30° - \sin30°)+1.5\times 9.81\times 0.2}{1.5+0}}\\\\=\sqrt{\frac{6.618}{1.5}}\\\\=4.412m/s

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A team of scientists wants to conduct a study on an endangered animal inthe wild. Which rule should the study follow in order to
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