First add 2y to both sides so 4 + 3x + 2y = 0 then subtract 4 from both sides so 3x + 2y = -4 that is standard form now subtract 3x from both sides 2y = 3x - 4 now divide by 2 on both sides y = 1.5x - 2 This is solved for y and is slope intercept form starting from original subtract 4 from both sides so 3x = -2x -4 now divide by 3 on both sides so x = -2/3x -4/3 this is solved for x hope any of that is what you needed.
Hello : <span>f(x)=x²+4x-5 </span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 : </span>f(x) = (x+2)² + b f(x) x²+4x+4+b= x² +4x-5 4+b= -5 b = -9 the vertex is : (2 , -9)
