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schepotkina [342]
4 years ago
10

in a survey 46 people which was 20% of those surveyed chose red as their favorite color how many people are surveyed ​

Mathematics
2 answers:
fiasKO [112]4 years ago
5 0
230
Explanation: because 46 is 20% then you would have to multiply it by 5 because 20 times 5 would equal to 100% which is everyone
Mademuasel [1]4 years ago
4 0

Answer:230

Step-by-step explanation:

To get to 100% you need to do 20% 5 times so if 46 people is 20% 46x5 will give you 100% of people surveyed

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jeyben [28]
I think 29 because Samantha is 5 year older than Luis
4 0
3 years ago
What is the value of the expression ?
zubka84 [21]

The value of this expression is 3 x 10^{6}


In order to find this, you divide each term separately. First we'll start with the numbers in the front.


\frac{4.8}{1.6} = 3


Now that we have the first number, we look to the 10s and the powers they are raised to. Since we are looking at powers of the same number, we can use the properties of exponents to simply subtract the numbers they are raised to.


\frac{10^{9}}{10^{3}}  = 10^{6}


Then we put the two back together for the final answer.


3 x 10^{6}

7 0
3 years ago
Common Tangents and AAA theorems
lubasha [3.4K]
You know from similar triangles that ...
  KM/KO = LM/LN
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  2(20 +x) = 3x
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Subtracting 2x, we get
  40 = x . . . . . . . . . . the measure of LM

The Pythagorean theorem tells us
  (LN)² +(NM)² = (LM)²
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5 0
4 years ago
SCALCET8 3.9.017.MI. Two cars start moving from the same point. One travels south at 48 mi/h and the other travels west at 20 mi
Veronika [31]

Answer:

The rate at which the distance between the cars increasing two hours later=52mi/h

Step-by-step explanation:

Let

Speed of one car, x'=48 mi/h

Speed of other car, y'=20 mi/h

We have to find the rate at which the distance between the cars increasing two hours later.

After 2 hours,

Distance traveled by one car

x=48\times 2=96 mi

Using the formula

Distance=Time\times speed

Distance traveled by other car

y=20\times 2=40 mi

Let z be the distance between two cars after 2 hours later

z=\sqrt{x^2+y^2}

Substitute the values

z=\sqrt{(96)^2+(40)^2}

z=104 mi

Now,

z^2=x^2+y^2

Differentiate w.r.t t

2z\frac{dz}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}

z\frac{dz}{dt}=x\frac{dx}{dt}+y\frac{dy}{dt}

Substitute the values

104\frac{dz}{dt}=96\times 48+40\times 20

\frac{dz}{dt}=\frac{96\times 48+40\times 20}{104}

\frac{dz}{dt}=52mi/h

Hence, the rate at which the distance between the cars increasing two hours later=52mi/h

3 0
3 years ago
Y=-1 and 1/4x+5<br>y=x+2<br>answer choice<br>a.(-5,-3)<br>b.(12/5,22/5)<br>c.(1,3)<br>SHOW WORK !!
-BARSIC- [3]
Answer is B. Work attached. :)

5 0
3 years ago
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