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2 years ago

A solution has a [H3O+] of 1 × 10−3 M. What is the [OH−] of the solution?

Chemistry

1 answer:

Marina CMI [18]2 years ago

5 0

Answer:

D. 1x10⁻¹¹ M

Explanation:

For any given aqueous solution the following formula is true:

1x10⁻¹⁴ = [H₃O⁺] * [OH⁻]

1x10⁻¹⁴ is the ion-product constant of water, Kw.

We input the given value of [H₃O⁺]:

1x10⁻¹⁴ = 1x10⁻³ * [OH⁻]

And solve for [OH⁻]:

[OH⁻] = 1x10⁻¹¹ M

Thus the correct answer is option D. 1x10⁻¹¹ M.

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A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor

AlexFokin [52]

Answer : The partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of $C_2HBrClF_3$ = 15.0 g

Mass of $O_2$ = 22.6 g

Molar mass of $C_2HBrClF_3$ = 197.4 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_2HBrClF_3$ and $O_2$ .

$\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole$

and,

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole$

Now we have to calculate the mole fraction of $C_2HBrClF_3$ and $O_2$ .

$\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971$

and,

$\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903$

Now we have to partial pressure of $C_2HBrClF_3$ and $O_2$ .

According to the Raoult's law,

$p^o=X\times p_T$

where,

$p^o$ = partial pressure of gas

$p_T$ = total pressure of gas

$X$ = mole fraction of gas

$p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T$

$p_{C_2HBrClF_3}=0.0971\times 862torr=84torr$

and,

$p_{O_2}=X_{O_2}\times p_T$

$p_{O_2}=0.903\times 862torr=778torr$

Therefore, the partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

6 0

2 years ago

1. In the models, what particles do the colored and plain sesame seeds represent? What particles do the poppy seeds represent

Veronika [31]

Ok the answers to the hole .doc is
1. Neutrons, Protons, and Electrons
2. Nucleus
3. Neutrons and Protons
4. Electrons
5. Because they represent different things (I would put this in your own words)

6 0

3 years ago

Read 2 more answers

A toaster has a resistance of 28 Ω and is plugged into a 110 V circuit. Using the GRASS method, what current is measured?

BARSIC [14]

Answer:

The current of the toaster is 3.93A

Explanation:

Using the GRASS method:

G: Given: The information that is given is that we have 28Ω of Resistance and 110V of voltage.

R: Required: We need to find the current measured.

A: Action: We can use Ohm's law that relates resistance, voltage and current in the equation:

V = R*I

Or:

I = V/R

Where I is current in A, V is voltage = 110V and R is resistance = 28Ω

S: Solve:

I = 110V / 28Ω

I = 3.93A

S: Statement:

<h3>The current of the toaster is 3.93A</h3>

4 0

3 years ago

How many moles of sulfur will be needed to react with 5.00 grams of aluminum?

Pachacha [2.7K]

Answer:

9584738373848838e7e8e

6 0

2 years ago

Metal M has only one oxidation state and forms a compound with the formula MHCO3. Which formula is correct? A.MNO3 b.MNH4 c.M(NO

never [62]

Answer:

The compound with the correct formula is;

A. MNO₃

Explanation:

The number of oxidation states in the metal, M = One oxidation state

The formula of the compound formed by the metal, M = MHCO₃

We note that the ion HCO₃⁻, known as hydrogen carbonate has an oxidation number of -1

Similarly nitrate, NO₃⁻ has an oxidation number of -1, therefore, the metal M can form similar compound formed with HCO₃⁻ with nitrate, and we have;

The possible compounds formed by the metal 'M' includes MHCO₃ and MNO₃.

5 0

2 years ago