Question

A reaction of 2.5kg of fissionable material takes place. Assuming a 0.10% mass defect, how much energy is released?

Answer 1

Answer:

Energy released = $2.25\times 10^{14}\;J$

Explanation:

Amount of fissionable material = 2.5 kg

Mass defect = 0.10 % of fissionable material

Mass defect $=2.5\times \frac{0.1}{100} = 0.0025\; kg$

$E = mc^{2}$

Where,

m = Mass defect in Kg

C = Speed of light m/s2

$C = 3\times 10^{8}\;m/s^2$

Now substitute the values in the above equation

$E = 0.0025\times (3\times 10^{8})^2 = 2.25\times 10^{14}\;J$