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3 years ago

What is neutralization ?

Chemistry

1 answer:

blagie [28]3 years ago

5 0

Answer:

"a chemical reaction in which acid and a base react quantitatively with each other"

Explanation:

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Choose the aqueous solution below with the lowest freezing point. These are all solutions of nonvolatile solutes and you should

atroni [7]

Answer:

$(NH_4)_3PO_4$ 0.075 m solution has the lowest freezing point.

Explanation:

Depression in freezing point is given by:

$\Delta T_f=T-T_f$

$\Delta T_f=K_f\times m$

$\Delta T_f=iK_f\times \frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in Kg}}$

where,

$\Delta T_f$ =Depression in freezing point

$K_f$ = Freezing point constant of solvent

1 - van't Hoff factor

m = molality

According question, molality of all the solutions are same and are in prepared with same solvent. So, values of molality and $K_f$ will remain the same and will not effect the freezing point of the solution.

The lowering in freezing point will now depend upon van't Hoff factors of the solutions. Higher the value of van'Hoff factor more will be the lowering in freezing point of the solution.

The van't Hoff factor of $KNO_2$ solution = $i_1=2$

The van't Hoff factor of $LiCN$ solution = $i_2=2$

The van't Hoff factor of $(NH_4)_3PO_4$ solution = $i_3=4$

The van't Hoff factor of $NaI$ solution = $i_4=2$

The van't Hoff factor of $NaBrO_3$ solution = $i_5=2$

The solution of ammonium phosphate has the highest values of van't Hoff factor which will result in maximum lowering of the freezing point of the solution.

Hence, $(NH_4)_3PO_4$ 0.075 m solution has the lowest freezing point.

4 0

3 years ago

Read 2 more answers

The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins

saul85 [17]

The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. $(1/2)^{n} = x$ ,
where:
n - a number of half-lives
x - a remained fraction of a sample

2. $t_{1/2} = \frac{t}{n}$
where:
 $t_{1/2}$ - half-life
t - total time elapsed
n - a number of half-lives

So, we know:
t = 10 min
 $t_{1/2}$ = 2.5 min

We need:
n = ?
x = ?

We could first use the second equation to calculate n:
If:
$t_{1/2} = \frac{t}{n}$ ,
Then:
$n = \frac{t}{ t_{1/2} }$
⇒ $n = \frac{10 min}{2.5 min}$
⇒ $n=4$ 

Now we can use the first equation to calculate the remained fraction of the sample.
 $(1/2)^{n} = x$
⇒ $x=(1/2)^4$
⇒ $x= \frac{1}{16}$

3 0

3 years ago

Chemistry Help (Naming Oxyacids Chart)

guapka [62]

Answer:

HClO₃ /chloric acid /suffix -ic/ ClO₃⁻ (chlorate)

HClO₂/ chlorous acid/ suffix -ous/ ClO₂⁻ (chlorite)

HNO₃ /nitric acid /suffix -ic/ NO₃⁻ (nitrate)

HNO₂/ nitrous acid/ suffix -ous/ NO₂⁻ (nitrite)

Explanation:

Chlorine has 4 positive oxidation numbers to form oxyacids: +1, +3, +5 and +7.

When it uses the oxidation number +5, it forms HClO₃, which is named chloric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion ClO₃⁻ (chlorate).

When it uses the oxidation number +3, it forms HClO₂, which is named chlorous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion ClO₂⁻ (chlorite).

Nitrogen has 2 positive oxidation numbers to form oxyacids: +3 and +5.

When it uses the oxidation number +5, it forms HNO₃, which is named nitric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion NO₃⁻ (nitrate).

When it uses the oxidation number +3, it forms HNO₂, which is named nitrous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion NO₂⁻ (nitrite).

7 0

3 years ago

In ____________, electrons are gained by atoms and lost by others

Nat2105 [25]

In ions atoms lose and gain electrons

3 0

3 years ago

Read 2 more answers

Which of the following is not true of atoms?

Alexandra [31]

Answer:

they are composed of water