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Elis [28]
3 years ago
11

What is a specialised cell?

Chemistry
1 answer:
Arlecino [84]3 years ago
8 0

Answer:

Hello, how is your day?

Explanation:

Specialised cells have a specific role to perform. Each specialised cell has a different job to do. They have special features that allow them to do these jobs. Muscle cells, for example, are held together in bundles, which pull together to make muscles contract.

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The density of whole milk 1.04 g per mL. What is the volume (in quarts) of 18.5 pounds of whole milk?
nadya68 [22]

The volume : 8,526 quarts

<h3>Further explanation</h3>

Given

The density of whole milk = 1.04 g/ml

mass = 18.5 pounds

Required

The volume

Solution

Conversion of mass

1 pound = 453,592 g

18.5 pounds = 8391,45 g

Density formula:

\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}.

Input the value :

V = m : ρ

V = 8391,45 g : 1.04 g/ml

V = 8068.7 ml

1 ml = 0,00105669 quarts

8068.7 ml =8,526 quarts

3 0
3 years ago
Would the ph at the equivalence point be acidic, basic, or neutral for each given titration?.
Lesechka [4]

Answer:

At the equivalence point, equal amounts of H+ and OH– ions will combine to form H2O, resulting in a pH of 7.0 (neutral). The pH at the equivalence point for this titration will always be 7.0, note that this is true only for titrations of strong acid with strong base.

Explanation:

3 0
2 years ago
Write the electron configuration for a sodium cation with a charge of 1+
Dafna1 [17]

1{s}^{2} 2 {s}^{2} 2 {p}^{6}

or simply 2,8 it is isoelectronic with argon

4 0
3 years ago
Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)
Fynjy0 [20]

Answer:

Rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

Explanation:

According to equation   2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

                     ⇒ -\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}  -----------------------------(1)

    Given that the rate of disappearance of oxygen = -\frac{d[O_{2} ]}{dt} = 3.64 x 10⁻³ M/s

             So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = ?

from equation (1) we can write

                                   \frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]

                                ⇒ \frac{d[SO_{3}] }{dt} = 2 x 3.64 x 10⁻³ M/s

                                ⇒ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

7 0
4 years ago
What variable represents specific heat in the equation Q = mcAT?
Elan Coil [88]

Answer: A. The variable c

============================================

Explanation:

Q = heat transferred

m = mass

c = specific heat

\Delta T = delta T = change in temperature

4 0
3 years ago
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