Answer: d) 
and 
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
A neutralization reaction is a double displacement reaction in which an acid reacts with base to produce salt and water. The 
ions from water reacts with 
ions from base to give water.
Thus products that will be released when the antacid is mixed with the hydrochloric acid in the stomach are and
E = hc/(lamda)
The lamda symbol is wavelength, which this site does not have. I can represent it with an "x" instead.
Plancks constant, h = 6.626×10^-32 J·s
Speed of light, c = 3.00×10^8 m/s
The energy must be greater than or equal to 1×10^-18 J
1×10^-18 J ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / x
x ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / (1×10^-18 J)
x ≤ 1.99×10^-7 m or 199 nm
The wavelength of light must be greater than or equal to 199 nm
Answer:
mL
Explanation:
Atmospheres (atn), Torr, and mm of Hg are all units of pressure but mL is a unit of volume, not pressure.
The characteristic is uniformity.
<h3>Uniformity of money</h3>
Money is said to be uniform because irrespective of the nature it exists, the same amount must have the same purchasing power.
For example, a dollar in paper form and a dollar in coin form must be able to buy the same 1 dollar worth of goods.
Thus, a dollar bill, irrespective of its age, has the same purchasing power as a new, crisp dollar bill.
More on uniformity of money can be found here: brainly.com/question/17039370
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<u>Answer:</u> The outermost valence electron enters the p orbital.
<u>Explanation:</u>
Valence electrons are defined as the electrons which are present in outer most orbital of an atom.
Sulfur is the 16th element of the periodic table having 16 electrons.
Electronic configuration of sulfur atom is 
The number of valence electrons are 2 + 4 = 6
These 6 electrons enter s-orbital and p-orbital but the outermost valence electron will enter the p-orbital.
Hence, the outermost valence electron enters p orbital.
