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astraxan [27]
3 years ago
11

The of the ocean floor would be the hardest to recover the cargo from.

Chemistry
1 answer:
kifflom [539]3 years ago
3 0

The of the ocean floor would be the hardest to recover the cargo form is Abyssal Plain

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LAB: predicting products
kondor19780726 [428]

Answer:

1) synthesis MgI2

2) double replacement CuS + (HCl)2

3) double replacement, not sure ab the formula sorry

4 0
2 years ago
Chemist question, helppp pls
Doss [256]

1: it is +2

2: it is +6

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8 0
3 years ago
There are ________ unpaired electrons in the Lewis symbol for a nitride ion.
Anna71 [15]

Answer:

There are no unpaired electrons.

Explanation:

There are  no unpaired electrons in the Lewis symbol for a nitride ion({ N }^{ 3- }).The nitride ion has a charge of -3. The negative charge on the Nitride ion indicates a gain in electrons . Nitrogen has 5 valence electrons that is the number of electrons that are in its outer shell .The total number of electrons that the nitride ion has is equal to 5+3 = 8 electrons . Electrons usually appear in pairs and obey the octet rule therefore the nitride ion has four electron pairs no unpaired electrons.

5 0
3 years ago
A scuba diver knows that she needs 50.0mol of air for an upcoming dive. What size (volume) tank will she need to fill for this d
erica [24]

Answer:

1120 L.

Explanation:

Hello!

In this case, as no conditions of pressure of temperature are given for this problem, we can assume that the scuba diver dives at STP (1 atm and 273.15 K), which means that 1 mole of air would occupy a volume of 22.4 L.

In such a way, since she needs 50.0 moles of air, the following ratio is useful to compute the size (volume) of the tank she needs:

V_2=\frac{V_1*n_2}{n_1}

Thereby, we plug in to obtain:

V_2=\frac{22.4L*50.0mol}{1mol}\\\\V_2=1120 L

Best regards!

4 0
3 years ago
NEED HELP!<br> Please refer to the picture for the question!
Mashutka [201]

Answer: i think the best bet i can give you is Option C (2:3)

Explanation: i apologize i haven't done chem in 2 years

but however to put it in retrospect the finished equation is 2(AL)^+3 3(O)^-2

4 0
3 years ago
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