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3 years ago

hich subatomic particle has a neutral charge? A) electron B) neutron C) nucleus Eliminate D) proton

2 answers:

8 0

The subatomic particle with a neutral charge is a neutron. I remember it because they both start with N. I remember protons have a positive charge, they both start with p, and electrons have a negative charge. It is just the last option, there is no device I use to remember it.

Anni [7]3 years ago

4 0

The subatomic particle with a neutral charge is the NEUTRON.

Unlike the proton which has a positive charge, and the electron that has a negative charge, the NEUtron has a NEUtral (no) charge.

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A blacksmith heated an iron bar to 1445 °C. The blacksmith then tempered the metal by dropping it into 42,800 mL of

Wittaler [7]

Answer:

6626 g

Explanation:

Given that:

Density of water = 1.00 g/ml, volume of water = 42800 ml.

Since density = mass/ volume

mass of water = volume of water * density of water = 42800 ml * 1 g/ml = 42800 g

Initial temperature of water = 22°C and final temperature of water = 45°C.

specific heat capacity for water = 4.184 J/g°C

ΔT water = 45 - 22 = 23°C

For iron:

mass = m,

specific heat capacity for iron = 0.444 J/g°C

Initial temperature of iron = 1445°C and final temperature of water = 45°C.

ΔT iron = 45 - 1445 = -1400°C

Quantity of heat (Q) to raised the temperature of a body is given as:

Q = mCΔT

The quantity of heat required to raise the temperature of water is equal to the temperature loss by the iron.

Q water (gain) + Q iron (loss) = 0

Q water = - Q iron

42800 g × 4.184 J/g°C × 23°C = -m × 0.444 J/g°C × -1400°C

m = 4118729.6/621.6

m = 6626 g

8 0

3 years ago

HELP WHAT NUMBER DOES IT SHOW??

zubka84 [21]

Answer:

its shows 28.4 ml

......

8 0

3 years ago

Read 2 more answers

What is the structural formula for 2-methyl 3-ethylbutane?

ivann1987 [24]

Answer:

Explanation:

2-methyl-3-ethylpentane | C8H18 | ChemSpider.

Boiling Point: 115.3±7.0 °C at 760 mmHg

Molecular Formula: C8H18

Density: 0.7±0.1 g/cm 3

Enthalpy of Vaporization: 32.9±0.0 kJ/mol

4 0

4 years ago

How would you prepare 2-methyl-2-propanol via a grignard with dimethyl carbonate as your carbonyl source? show all reagents?

Andreas93 [3]

Answer:

React it with CH₃MgBr and work up the product with saturated ammonium chloride solution

Explanation:

Grignard reagents convert esters into tertiary alcohols.

The general equation is

$\text{RCOOR}' \xrightarrow[\text{2. H}^{+}]{\text{1. R$^{\prime \prime}$MgBr}}\text{RR$_{2}^{\prime \prime}$C-OH}$

The Grignard reagent in this synthesis is methylmagnesium bromide. You prepare it by reacting a solution methyl bromide in anhydrous ether with magnesium and a few crystals of iodine.

The reaction consumes 3 mol of CH₃MgBr per mole of dimethyl carbonate, and everything happens in the same pot.

Acid workup of the product usually involves the addition of a saturated aqueous solution of ammonium chloride and extraction with a low-boiling organic solvent.

The mechanism involves:

Step 1. Nucleophilic attack and loss of leaving group

(a) The Grignard reagent attacks the carbonyl of dimethyl carbonate, followed by (b) the loss of a methoxide leaving group.

Step 2. Nucleophilic attack and loss of leaving group

(a) A second mole of the Grignard reagent attacks the carbonyl of methyl acetate, followed by (b) the loss of a methoxide leaving group.

Step 3. Nucleophilic attack and protonation of the adduct.

(a) A third mole of the Grignard reagent attacks the carbonyl of acetone, followed by (b) protonation of the alkoxide to form 2-methylpropan-2-ol.

3 0

4 years ago

Write the symbol for nitrogen which has 9 neutrons<br><br>How do I solve this?

diamong [38]

If you mean lewis dot symbol you need a nuclide you get the number of proton (z) its equal to electrons since the atom is nutral then you make the elctron configuraion after that you take the number of electrons on the outer energy level( ex:k²L² in this case its the 2 on the L)and if you have 7 electrons and the atom is nitrogen so it becomes
_
:N:
.
Hope that helped

7 0

3 years ago