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svetoff [14.1K]
3 years ago
6

What is the structural formula for 2-methyl 3-ethylbutane?

Chemistry
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

Explanation:

2-methyl-3-ethylpentane | C8H18 | ChemSpider.

Boiling Point: 115.3±7.0 °C at 760 mmHg

Molecular Formula: C8H18

Density: 0.7±0.1 g/cm 3

Enthalpy of Vaporization: 32.9±0.0 kJ/mol

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Similarities between pluton and pegmatite
snow_lady [41]
Plutons are large chambers of magma under grown

pegmatites generally form in pluton so it cools slow enough to make the crystals big enough to be classified as pegmatite and not just granite
7 0
3 years ago
Heavy nuclides with too few neutrons to be in the band of stability are most likely to decay by what mode?
Margarita [4]

Answer:

Positron emission

Explanation:

Positron emission involves the conversion of a proton to a neutron. This process increases the mass number of the daughter nucleus by 1 while its atomic number remains the same. The new neutron increases the number of neutrons present in the daughter nucleus hence the process increases the N/P ratio.

A positron is usually ejected in the process together with an anti-neutrino to balance the spins.

6 0
3 years ago
Which of the following acids should be used to prepare a buffer with a pH of 4.5?A. HOC6H4OCOOH, Ka = 1.0 x 10^-3B. C6H4(COOH)2,
ioda

Answer:

C. CH3COOH, Ka = 1.8 E-5

Explanation:

analyzing the pKa of the given acids:

∴ pKa = - Log Ka

A. pKa = - Log (1.0 E-3 ) = 3

B. pKa = - Log (2.9 E-4) = 3.54

C. pKa = - Log (1.8 E-5) = 4.745

D. pKa = - Log (4.0 E-6) = 5.397

E. pKa = - Log (2.3 E-9) = 8.638

We choose the (C) acid since its pKa close to the expected pH.

⇒ For a buffer solution formed from an acid and its respective salt, we have the equation Henderson-Hausselbach (H-H):

  • pH = pKa + Log ([CH3COO-]/[CH3COOH])

∴ pH = 4.5

∴ pKa = 4.745

⇒ 4.5 = 4.745 + Log ([CH3COO-]/[CH3COOH])

⇒ - 0.245 = Log ([CH3COO-]/[CH3COOH])

⇒ 0.5692 = [CH3COO-]/[CH3COOH]

∴ Ka = 1.8 E-5 = ([H3O+].[CH3COO-])/[CH3COOH]

⇒ 1.8 E-5 = [H3O+](0.5692)

⇒ [H3O+] = 3.1623 E-5 M

⇒ pH = - Log ( 3.1623 E-5 ) = 4.5

6 0
3 years ago
Why does the concentration of a product increase as the amount of the reactant decreases? (More 10+ pt questions on profile)
skad [1K]
As reactant concentration decreases, the forward. reaction slows. As product concentration increases, the reverse reaction becomes faster. The forward. reaction will continue to slow and the reverse reaction will continue to increase until they are the same.Then the situation will be at equilibrium.
8 0
3 years ago
20 points!!!
MariettaO [177]

I don't know if this was your answer choice but I actually got the answer to be toothpaste.

hydrated alumina, calcium carbonate, make up toothpaste

Again idk if this was an answer choice but I hope this helps, have a good day, sorry if not. c;

5 0
3 years ago
Read 2 more answers
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