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3 years ago

14

Joel uses a crew hammer to remove a nail from a wall . He applied a force 40 newtons on the hammer. The hammer applied a force o

f 160 newtons on the nail . The mechanical advantage of the hammer is ____.

1 answer:

zaharov [31]3 years ago

3 0

By mechanical advantage 160/40=4

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Look at the circuit diagram. Which of these components is part of the circuit?

Roman55 [17]

Answer:

b ac power source

Explanation:

ieififuffucjcjcicogore8e8e9e9e9e9ew0ww0w0w

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2 years ago

A laser beam with a frequency of 180 Hz forms an 8 m standing wave with 10 nodes.

DIA [1.3K]

Answer:33

Explanation:

F = frequency

N = Node count

w = wave lenght

v = wave velocity

L = distance wave traveled

First find wave length of laser

w = (2/(N))*(L)

w = (2/(10))*(8)

w = 1.6

then using (w), find velocity

V = (w)(F)

V = (1.6)*(108)

V = 288

Plug in V and the new frequency to solve for new node count

F = NV/2L

(600) = (N)*(288) / 2 * (8)

(N) = 33.33

there are 33 nodes

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2 years ago

Complete this sentence. If the mass of object A is __________ than object B, then the weight of object A will be _______________

AfilCa [17]

Answer:

Complete this sentence. If the mass of object A is greater than object B, then the weight of object A will be heavier the weight of object B.

Explanation:

If the mass of Object A is more/greater than object B then it would be "heavier"

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2 years ago

Read 2 more answers

When one person shouts at a football game, the sound intensity level at the center of the field is 58.4 dB. When all the people

Tanzania [10]

Answer:

The number of people at game are approximately 22909

Explanation:

Given data

When one person shout $\beta _{1}=58.4dB$

When n number of person shout together $\beta _{n}=102dB$

The sound intensity level during one person shout is given by:

$\beta _{1}=10log(\frac{I_{1}}{I_{o}} )\\58.4=10log(\frac{I_{1}}{I_{o}} )\\5.84=log(\frac{I_{1}}{I_{o}} )\\\frac{I_{1}}{I_{o}} =10^{5.84}\\I_{1}=10^{5.84}*I_{o}$

The sound intensity level during n number of person shout is given by:

$\beta _{n}=10log(\frac{I_{n}}{I_{o}} )\\102=10log(\frac{I_{n}}{I_{o}} )\\10.2=log(\frac{I_{n}}{I_{o}} )\\\frac{I_{n}}{I_{o}}=10^{10.2}\\I_{n}=10^{10.2}*I_{o}$

Since each person generates same sound intensity and hence total number of persons can be determined as

$=\frac{I_{n}}{I_{1}}\\ =\frac{10^{10.2}I_{o}}{10^{5.84}I_{o}} \\=22909$

Hence

The number of people at game are approximately 22909

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2 years ago

Read 2 more answers

cheAt an amusement park, a swimmer uses a water slide to enter the main pool. If the swimmer starts at rest, slides without fric

KiRa [710]

Answer:

$v \approx 7.371\,\frac{m}{s}$

Explanation:

The swimmer can be modelled by the Principle of Energy Conservation. The speed is derived herein:

$m_{swimmer}\cdot g \cdot h = \frac{1}{2}\cdot m_{swimmer}\cdot v^{2}$

$v = \sqrt{2\cdot g \cdot h}$

$v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (2.77\,m)}$

$v \approx 7.371\,\frac{m}{s}$

3 0

3 years ago