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jekas [21]
3 years ago
12

An aluminum rod is 10.0 cm long and a steel rod is 80.0 cm long when both rods are at a temperature of 15°C. Both rods have the

same diameter. The rods are now joined end-to-end to form a rod 90.0 cm long. If the temperature is now raised from 15°C to 90°C, what is the increase in the length of the joined rod? The coefficient of linear expansion of aluminum is 2.4 × 10-5 K-1 and that of steel is 1.2 × 10-5 K-1.
Physics
1 answer:
Lesechka [4]3 years ago
4 0

Answer:

0.9 cm

Explanation:

The computation in the increase in the length of the joined rod is shown below:

As we know that

Increase in length = increase in the length of aluminum rod + increase in The length of steel rod

= 10cm \times 2.4e - 5\times (90-15) + 80cm\times 1.2e - 5\times (90-15)

= 0.9 cm

We simply added the length of aluminium rod and length of steel rod so that the length of the joined rod could come and the same is to be considered  

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Two blocks with mass M and 3M on a horizontal frictionless surface are pushed together and compress a spring of negligible mass
Naily [24]

Answer:

launching speed of the lighter block = -6 m/s

Explanation:

We are given;

Mass of light block; M

Mass of heavy block; 3M

Speed of launched block: v = 2m/s

We are told that the two blocks are sitting on the horizontal frictionless surface. Thus, we can say that no external force is being applied on the system and so, the momentum of the whole system is conserved accordingly to that condition.

We are also told that when the rope is cut with scissors, that the heavier block attains the speed of 2 m/s in the positive x-direction which is horizontal direction.

We know that formula for momentum is; M = mass x velocity.

Thus, the momentum of the heavier block is calculated as;

M_1 = 3M × 2

M_1 = 6M kg.m/s

Since no external force is applied on the object, the initial momentum will be zero.

Hence, to conserve the system, the momentum of the lighter block will be equal and opposite to the momentum of heavier block.

So, momentum of lighter block is;

M_2 = -6M kg.m/s

Since mass of lighter block is M and formula for momentum = mass x velocity.

Thus;

-6M = Mv

Where v is speed of lighter block.

So, v = -6M/M

v = -6 m/s

7 0
3 years ago
How to find the velocity of an object in a circular path?
Luda [366]
First of all, let's just talk about the speed, and not get wound up
in the velocity. OK ?

If a fly is sitting on the rim of the wheel and the wheel is rotating, then for
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wheel, which is (2 π) x (radius of the wheel).

In 'N' revolutions, the fly travels (2 N π) x (the radius). and so on.

So if the wheel is going, let's say 71 revs per minute (RPM), a point
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Another way to say it:

Speed of a point on the circle = (2 π) x (rotation frequency) x (radius).

The 'rotation frequency' takes care of the unit of time, and the 'radius'
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7 0
3 years ago
Read 2 more answers
The player that possess the best ball handling skills and usually handles the ball often
velikii [3]

The player that possess the best ball handling skills and usually handles

the ball often is referred to as the point guard.

Point guards in basketball are referred to as the players who have certain

characteristics such as speed ,an excellent ball handling skills and

leadership qualities.

Point guards is similar to the creative midfielder in soccer which helps to

dictate play and create chances for other team mates which is why they

handle the ball often.

Read more on brainly.com/question/25759951

4 0
3 years ago
Why do the passengers in high-altitude jet planes feel the sensation of weight while passengers in an orbiting space vehicle, su
kykrilka [37]

Passengers in an aircraft are subject to the Normal and Gravity Force acting on them at a low 'orbit', so tiny that it can be many times compared to the same surface of the earth when speaking in general terms.

In a high orbit space vehicle or in the same space, said force decreases considerably or simply disappears, generating the sensation of weightlessness.

Remember that the Force of Gravity is given under the principle

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When the radius grows considerably the gravitational force begins to decrease.

7 0
2 years ago
A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi
vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

V=\frac {C_2V_2-C_1V_1}{C_1+C_2}

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}

Therefore

V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437

Charge, Q is given by CV hence for the first capacitor charge will be Q_1=C_1V

Here, Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C

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