Answer:
Explanation:
Given that,
Current in loops are
i1 = 12A
i2 = 20A
The loops are 3.4cm apart
The magnetic field at the center is found to be zero, so when want to find the radius of bigger loop
Magnetic Field is given as
B= μoi/2πr
Where,
μo is a constant = 4π×10^-7 Tm/A
r is the distance between the two wires
i is the current in the wires
B is the magnetic field
NOTE
Field due to large loop should be equal to the smaller loop.
B1 = B2
μo•i1 / 2π•r1 = μo•i2 / 2π•r2
Then, μo, 2π cancels out, so we have
i1 / r1 = i2 / r2
Make r2 subject of formula
i1•r2 = i2•r1
r2 = i2•r1 / i2
r2 = 20×3.4/12
r2 = 5.67cm
The radius of the bigger loop is 5.67cm.
Magnitude is the word used to describe the amount of energy released by an earthquake.
Hope I helped! :D
I think the correct answer from the choices listed above is the last option. When electrical energy is converted into thermal energy, the <span>total amount of thermal energy plus electrical energy doesn't change. This is base on the Law of Conservation of energy where energy cannot be created or destroyed. </span>
Answer:
= 925.92 N
≅ 926N
Explanation:
Pressure due to car = pressure due to applied force
12000/18^2 = Force / 5^2
force = 12000 * 25/ 324
= 925.92 N
For equilibrium
Pressure1 = Pressure2
A1F1 = A2F2
12000*pi*(5^2) = F2 ( pi)*(18^2)
so, F2 = Applied force to lift car = 925.92 N
Pascal's principle
Pressure1 = Pressure2
F1/A1 = F2/A2 (F=force and A=area)
A1 =Pi*(0.05)²
A2 =Pi(0.18)²
F2=12000
F1 = 12000*(0.05)² / (0.18)² = 926N