A zinc atom has 7 electrons. to what level are it's electrons found

Determine the length of a wind instrument, assuming that it is modeled as a closed tube and that the lowest sound that it can pl

denis-greek [22]

Answer:

length = 1.24m

Explanation:

velocity = frequency x wavelength

wavelength = velocity/frequency

w = 343/69 =4.97m

length = wavelength/4

length =4.97/4 =1.24m

3 0

3 years ago

An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.220 T. If the kinetic energy of the electr

Gwar [14]

Answer:

$971605.66\ \text{m/s}$

$25.1\ \mu\text{m}$

Explanation:

m = Mass of electron = $9.11\times 10^{-31}\ \text{kg}$

B = Magnetic field = 0.22 T

K = Kinetic energy of electron = $4.3\times 10^{-19}\ \text{J}$

q = Charge = $1.6\times 10^{-19}\ \text{C}$

v = Velocity of electron

r = Radius of curved path

Kinetic energy is given by

$K=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{\dfrac{2K}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 4.3\times 10^{-19}}{9.11\times 10^{-31}}}\\\Rightarrow v=971605.66\ \text{m/s}$

The speed of the electron is $971605.66\ \text{m/s}$

The force balance of the system is given by

$qvB=\dfrac{mv^2}{r}\\\Rightarrow r=\dfrac{mv}{qB}\\\Rightarrow r=\dfrac{9.11\times 10^{-31}\times 971605.66}{1.6\times 10^{-19}\times 0.22}\\\Rightarrow r=0.0000251=25.1\ \mu\text{m}$

The radius of the curved path is $25.1\ \mu\text{m}$

6 0

3 years ago

Question 17 of 25

Scorpion4ik [409]

Answer:

The speed of the wave as it travelled through the brass bell is;

B. 4,700 m/s

Explanation:

The given parameters are;

The wavelength of the sound wave produced from the brass bell, $\lambda _{(air)}$ = 3.5 m

The wavelength of the wave in the brass bell, $\lambda _{(brass \ bell)}$ = 47 m

The frequency of the wave in the brass bell, f = 100 Hz

The given equation for wave speed, v = f × λ

Therefore, the speed of the wave as it travelled through the brass bell, $v _{(brass \ bell)}$ , is given as follows;

$v _{(brass \ bell)}$ = f × $\lambda _{(brass \ bell)}$ = 100 Hz × 47 m = 4,700 m/s

The speed of the wave as it travelled through the brass bell = $v _{(brass \ bell)}$ = 4,700 m/s

5 0

3 years ago

Read 2 more answers

Object A with a mass of 500 kilograms hits stationary object B with a mass of 920 kilograms. If the collision is elastic, what h

Vika [28.1K]

In elastic collision, both the kinetic energy and momentum are conserved. Conservation means that both the kinetic energy and momentum will have the same values before and after elastic collision.

<span>As the object A has low mass than object B. Hence upon collision, object B moves forward, while object A will move backward. So option "C" is correct. </span>

5 0

4 years ago

A gas expands from an initial volume of 0.040 m^3 and an initial pressure of 210 kPa to a final volume of 0.065 m^3 while its te

USPshnik [31]

Answer:

286

Explanation:

p1v1/T1=p2v2/T2

then subtitude your values

T2=760*0.65*273/210*0.040

T2=135/8.4=16+273=289

7 0

4 years ago