Answer:
There's No Answer Im Sorry
Answer:
Order of increasing strength of intermolecular attraction:
>
>
> Ar
Explanation:
can form hydrogen bond as H atom is attached with electronegative atom O.
Rest three,
,
, Ar are non-polar molecules.
In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence,
has strongest intermolecular attractions.
Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.
Molecular size and mass of
is high as compared to
.
van der Waals intermolecular forces of attraction increases with increase in size.
Therefore,
Order of increasing strength of intermolecular attraction will be:
>
>
> Ar
The value of log₂(x/4) is 22. Using the properties of the logarithm, the required value is calculated.
<h3>What are the required properties of the logarithm?</h3>
The required logarithm properties are
logₐx = n ⇒ aⁿ = x; and logₐ(xⁿ) = n logₐ(x);
Where a is the base of the logarithm.
<h3>Calculation:</h3>
It is given that,
log₄(x) = 12;
On applying the property logₐx = n ⇒ aⁿ = x; here a = 4;
So,
log₄(x) = 12 ⇒ 4¹² = x
⇒ x = (2²)¹² = 2²⁴
Then, calculating log₂(x/4):
log₂(x/4) = log₂(2²⁴/4)
= log₂(2²⁴/2²)
= log₂(2²⁴ ⁻ ²)
= log₂(2²²)
On applying the property logₐ(xⁿ) = n logₐ(x);
log₂(x/4) = 22 log₂2
We know that logₐa = 1;
So,
log₂(x/4) = 22(1)
∴ log₂(x/4) = 22.
Learn more about the properties of logarithm here:
brainly.com/question/12049968
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Nitrogen is 5 valence electrons
oxygen is 6 valence electrons
fluorine is 7 electrons
Answer:
The answer is A.
Explanation:
C6H12O6 + 6O2 -> 6CO2 + 6H20
C6H12O6 + 6O2 -> 6CO2 + 6H20At the reactant side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.
atoms, 12 hydrogen atoms and 18 oxygen atoms.At product side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.
(In a balanced equation, the no. of atoms on the reactant side must be <em><u>e</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>l</u></em><em> </em>to the no. of atoms on the product side)