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rjkz [21]
3 years ago
13

A reaction progress curve has three peaks and two valleys between the peaks. This curve describes a reaction mechanism that invo

lves _____. A. three elementary reactions B. one compound decomposing into three parts C. three compounds combining together D. two elementary reactions

Chemistry
2 answers:
bekas [8.4K]3 years ago
6 0

The correct answer is Three elementary reactions

katrin [286]3 years ago
3 0
Answer:
            <span>A reaction progress curve has three peaks and two valleys between the peaks. This curve describes a reaction mechanism that involves <u>three elementary reactions</u>.

Explanation:
                   I have drawn the progress curve with three peaks and two valleys. In fact the peaks shows higher energy and valleys show lower energies. So, Let suppose we react A and B. This reaction between A and B results in the formation of C. In this reaction the energies of A and B are less, and during the progress of reaction they cross a transition state of higher energy and forms product C with lower energy which is present at lower valley. This was first reaction. Other two reactions will be followed by conversion of C to D and conversion of D into E.</span>

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vovikov84 [41]
V=4.8 L
c=5.0 mol/L
M(Mg)=24.3 g/mol

1) n(HCl)=cv

2) m(Mg)=M(Mg)n(HCl)/2

3) m(Mg)=M(Mg)cv/2
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Hay particulas mas pequeñas que el atomo?
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Una partícula subatómica es aquella que es más pequeña que el átomo. Puede ser una partícula elemental o una compuesta, a su vez, por otras partículas, como los quarks que componen los protones y los neutrones. ... De esta manera, se han descubierto docenas de partículas subatómicas, y se teorizan cientos de otras más.

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At a wastewater treatment plant, FeCl3(s) is added to remove excess phosphate from the effluent. Assume the following reactions
RoseWind [281]

Answer : The concentration of Fe^{3+} needed is, 2.37\times 10^4M

Explanation :

First we have to calculate the mole of phosphate.

As we are given that, 1 mg P/L that means, 1 mg of phosphate present in 1 L of solution.

\text{Moles of phosphate}=\frac{\text{Mass of phosphate}}{\text{Molar mass of phosphate}}

Molar mass of phosphate = 94.97 g/mole

\text{Moles of phosphate}=\frac{1mg}{94.97g/mol}=\frac{0.001g}{94.97g/mol}=1.053\times 10^{-5}mol

Now we have to calculate the concentration of phosphate.

\text{Concentration of phosphate}=\frac{\text{Moles of phosphate}}{\text{Volume of solution}}

\text{Concentration of phosphate}=\frac{1.053\times 10^{-5}mol}{1L}=1.053\times 10^{-5}mol/L

Now we have to calculate the concentration of Fe^{3+}.

The second equilibrium reaction is,

FePO_4\rightleftharpoons Fe^{3+}+PO_4^{3-}

The solubility constant expression for this reaction is:

K_{sp}=[Fe^{3+}][PO_4^{3-}]

Given: K_{sp}=\frac{1}{4}

\frac{1}{4}=[Fe^{3+}]\times 1.053\times 10^{-5}mol/L

[Fe^{3+}]=2.37\times 10^4M

Thus, the concentration of Fe^{3+} needed is, 2.37\times 10^4M

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4 years ago
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