Use the concentration and rate data presented in the table below to answer the following questions about the hypothetical reaction:
A + 2B + 4C→ 2D + E
<span><span>Line[A] (mol/L)[B] (mol/L)[C] (mol/L)Rate (mol/L.s)</span><span>10.1000.1000.1003.6 x 10-2</span><span>20.2000.1000.1003.6 x 10-2</span><span>30.1000.2000.1007.2 x 10-2</span><span>40.2000.2000.2002.9 x 10-1</span><span>50.3000.2000.300?</span></span><span>Why would you expect this reaction to be a multi-step reaction, based on the overall reaction?What is the order of the reaction, with respect to each reactant?What is the overall order of the reaction?Write the rate law equation.How does the rate law equation confirm that this is a multi-step reaction?Predict the rate indicated by the “?”Propose a reaction mechanism using the criteria presented in the lesson, with the third step as the rate-determining step.<span>Draw a potential energy diagram to illustrate this reaction mechanism, assuming that the overall reaction is endothermic. Label reaction intermediates with the “RI”, and activated complexes with “AC”</span></span>
I would say that you would need 12 to have it be equal for this reaction to happen. I hope that this helped. :)
Answer:
6 days
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Half life (t½) =?
Next, we shall determine the decay constant. This can be obtained as follow:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Decay constant (K) =?
Log (N₀/N) = kt / 2.303
Log (100/6.25) = k × 24 / 2.303
Log 16 = k × 24 / 2.303
1.2041 = k × 24 / 2.303
Cross multiply
k × 24 = 1.2041 × 2.303
Divide both side by 24
K = (1.2041 × 2.303) / 24
K = 0.1155 /day
Finally, we shall determine the half-life of the isotope as follow:
Decay constant (K) = 0.1155 /day
Half life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 0.1155
t½ = 6 days
Therefore, the half-life of the isotope is 6 days
Is there suppose to be a picture? Cause I do t see one
The correctanswer is D hope this helps
