PH=5.57
pH+pOH=14
5.57 + pOH=14
pOH = 14-5.57= 8.43
pOH = - log [OH⁻]
-pOH= log [OH⁻]
![[OH^{-}] = 10^{-pOH}= 10^{-8.43}= 3.72*10^{-9} [OH^{-}]= 3.72*10^{-9}](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%2010%5E%7B-pOH%7D%3D%2010%5E%7B-8.43%7D%3D%203.72%2A10%5E%7B-9%7D%0A%0A%20%5BOH%5E%7B-%7D%5D%3D%203.72%2A10%5E%7B-9%7D)
pH+pOH=14
5.57 + pOH=14
pOH = 14-5.57= 8.43
pOH = - log [OH⁻]
-pOH= log [OH⁻]
In a coupled reaction, energy needs to be created to drive a second reaction forward. True or false
1 answer:
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Answer:
See the attached file for the structure.
Explanation:
Find attached for the explanation
