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2 years ago

In a coupled reaction, energy needs to be created to drive a second reaction forward. True or false

Chemistry

1 answer:

erastovalidia [21]2 years ago

5 0

Answer:

I would say false.

Explanation:

Hope it helps:)

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Most of the energy released by nuclear fission is in the form of_________rays.

Margaret [11]

The answer to “most of the energy released by nuclear fission in the form of _____ rays.” is GAMMA RAYS

3 0

3 years ago

What's meant by the term enantiotropy?

Mila [183]

Answer:

the relation of two different forms of the same substance (such as two allotropic forms of tin) that have a definite transition point and can therefore change reversibly each into the other — compare monotropy.

7 0

3 years ago

Read 2 more answers

There are two naturally occurring isotopes of boron. 10 B has a mass of 10.0129 u. 11 B has a mass of 11.0093 u. Determine the a

Vanyuwa [196]

<h2>Natural Abundance for 10B is 19.60%</h2>

Explanation:

The natural isotopic abundance of 10B is 19.60%.

The natural isotopic abundance of 11B is 80.40%.

The isotopic masses of boron are 10.0129 u and 11.009 u respectively.

For calculation of abundance of both the isotopes -

Supposing it was 50/50, the average mass would be 10.5, so to increase the mass we need a more percentage of 11.

Determining it as an equation -

10x + 11y= 10.8

x+y=1 (ratio)

10x + 10y = 10

By taking the denominator away from the numerator

we get;

y = 0.8

x + y = 1

∴ x = 0.2

To get percentages we need to multiply it by 100

So, the calculated abundance is 80% for 11 B and 20% 10 B.

5 0

3 years ago

How many valence electrons does magnesium (Mg) have?Question options:A) 6B) 2C) 12D) 0

wel

INFORMATION:

We must find the number of valence electrons for magnesium

STEP BY STEP EXPLANATION:

In order to know the number of valence electrons for Mg, we need to locate the element in the periodic table

Since Mg is in the second group of the periodic table, it has two valence electrons.

ANSWER:

B) 2

4 0

1 year ago

A certain gas has a volume of 500.0 mL at 77.0°C and 600KPa. Calculate the temperature if the volume decreased to 400.0 mL and t

Jlenok [28]

Answer:

354.67K

Explanation:

Applying

P₁V₁/T₁ = P₂V₂/T₂................. Equation 1

Where Where P₁ = initial pressure, T₁ = Initial temperature, V₁ = Initial Volume, P₂ = Final pressure, V₂ = Final Volume, T₂ = Final Temperature.

From the question, we are ask to look for the final temperature,

Therefore we make T₂ the subject of the equation

T₂ = P₂V₂T₁/P₁V₁............. Equation 2

Given: P₁ = 600 kPa, V₁ = 500 mL, T₁ = 77 °C = (273+77) = 350 K, P₂ = 760 kPa, V₂ = 400.0 mL

Substitute these values into equation 2

T₂ = (760×400×350)/(600×500)

T₂ = 354.67 K

3 0

3 years ago