Answer:
36 miles.......................
Answer:
y = (x-.5)^2 -12.25
Step-by-step explanation:
first, find the vertex
x from (x,y) = -b/2a
ax^2-bx - c
1x^2-1x -12
-1/2(-1) = -1/-2 - 1/2
(1/2,y) then use x value to find y value
y = 1/2^2 - 1/2 - 12
y = .25 -.5 - 12 = -12.25
(.5,-12.25) input values into this formula:
y = a(x-h)^2 + k where h = x-value and k = y-value. use same a value = 1
y = (x-.5)^2 -12.25
Step-by-step explanation:
We assume that the advertising rates in this journal for full-page ads is x ($/ad); the rate for half-page ads is y ($/ad).
The revenue for 3 full page ads are: 3x ($)
The revenue for 5 half page ads are: 5y ($)
One issue of a journal has 3 full-page ads and 5 half-page ads, generating $6340.
=> The total revenue for 3 full page and 5 half page ads are $6340
=> 3x + 5y = 6340
The revenue for 4 full page ads are: 4x ($)
The revenue for 4 half page ads are: 4y ($)
One issue of a journal has 4 full-page ads and 4 half-page ads, generating $6625.
=> The total revenue for 4 full page and 4 half page ads are $6625
=> 4x + 4y = 6625 (1)
We have:
+) 3x + 5y = 6340
=> 5y = 6340 - 3x
=> y = (6340 - 3x)/5 = 1268 - 0.6x
Replace <em>y = 1268 - 0.6x </em>into (1), we have:
4x + 4y = 6625
⇔4x + 4(1268 - 0.6x) = 6625
⇔ 4x + 5072 - 2.4x = 6625
⇔ 1.6x = 1553
⇔ x = 1553/1.6 = 970.625
=> y = 1268 - 0.6x = 1268 - 0.6*970.625= 1268 - 582.375 = 685.625
So the advertising rate for full page ads is $970.625, for half-page ads is $685.625
Answer:
i think the answer is
225 beacuse 15×15=225=r^2
