Answer:
The answer is B, C, and E.
Explanation:
Saw this post and one other neither had the correct answer so i figured i would help anyone out that needs the correct answer.
Answer and Explanation:
The journal entry is shown below:
Cash Dr 30,000
Bank Dr 50,000
To Capital 80,000
(Being cash and bank brought into the business)
Here the cash and bank is debited as it increased the assets and credited the capital as it also increased the equity
Answer:
Kindly check explanation
Explanation:
Given the data:
x___ f(x)
10__ 0.05
20__0.10
30__0.10
40__0.20
50__0.35
60__0.20
a. Is this probability distribution valid?
Yes
Σf(x) = (0.05 + 0.10 + 0.10 + 0.20 + 0.35 + 0.20) = 1
0≤f(x)≤1
b. What is the probability MCC will obtain more than 30 new clients
X = 40 + x = 50 + x = 60
0.20 + 0.35 + 0.20 = 0.75
c. What is the probability MCC will obtain fewer than 20 new clients
x = 10
f(x) = f(10) = 0.05
d)Compute the expected value and variance of x.
Expected value (E(x)) :
Σ(x * f(x))
= (10*0.05) + (20*0.1) + (30*0.1) + (40*0.2) + (50*0.35) + (60*0.2)
= 43
Σ(x * E(x))² * f(x)
= (10 - 43)^2 * 0.05 + (20 - 43)^2 * 0.1 + (30 - 43)^2 * 0.1 + (40 - 43)^2 * 0.2+ (50 - 43)^2 * 0.35 + (60 - 43)^2 * 0.2
= 201
Answer:
Annual deposit= $99,722.29
Explanation:
Giving the following information:
Future value (FV)= $1,750,000
Number of years (n)= 10
Interest rate (i)= 12%
<u>To calculate the annual deposit, we need to use the following formula:</u>
FV= {A*[(1+i)^n-1]}/i
A= annual deposit
Isolating A:
A= (FV*i)/{[(1+i)^n]-1}
A= (1,750,000*0.12) / [(1.12^10) - 1]
A= $99,722.29