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Vladimir [108]
3 years ago
11

Arsenic produces a blue flame when heated. Calcium produces an orange-red flame. Which of these best explains why this differenc

e occurs?
Chemistry
1 answer:
MrMuchimi3 years ago
6 0

Flame colors are produced from the movement of the electrons in the metal ions present in the compounds. When you heat it, the electrons gain energy and can jump into any of the empty orbitals at higher levels Each of these jumps involves a specific amount of energy being released as light energy, and each corresponds to a particular color. As a result of all these jumps, a spectrum of colored lines will be produced. The color you see will be a combination of all these individual colors.

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For the reaction: h2(g) + cl2(g) → 2hcl(g), how many moles hcl will be produced from 10.0 g of h2? the reaction occurs in the pr
motikmotik
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3 0
3 years ago
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If a can of soup 150 g mass and 0.75g/ cm^3 density what’s the volume
Liula [17]

Answer:

<h3>The answer is 200 cm³</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}\\

From the question

mass = 150 g

density = 0.75 g/cm³

We have

volume =  \frac{150}{0.75}  \\

We have the final answer as

<h3>200 cm³</h3>

Hope this helps you

8 0
3 years ago
What is the total pressure of three gases, if the partial pressures are: 2.67 mmHg, 45.29 mmHg, and 789.6 mmHg
EastWind [94]

Answer:

The total pressure of three gases is 837.56 mmHg.

Explanation:

The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

PT = PA + PB

This relationship is due to the assumption that there are no attractive forces between the gases.

In this case, the total pressure can be calculated as:

PT= 2.67 mmHg + 45.69 mmHg + 789.6 mmHg

Solving:

PT= 837.56 mmHg

<em><u>The total pressure of three gases is 837.56 mmHg.</u></em>

7 0
3 years ago
A mixture of MgCl2 and NaCl has an initial mass of 0.4015 g. Excess AgNO3(aq) was added and 1.032 g of precipitate, AgCl(s), was
zlopas [31]

Answer:

8.909*10^-4 moles

Explanation:

The mixture contains MgCl_{2} and NaCl with a total mass of 0.4015 g. The mass of precipitate AgCl(aq) is 1.032 g and it has a molar mass of 143.32 g/mol. Therefore, the moles of the precipitate is:

n = 1.032/143.32 = 7.2007*10^-3 moles

Molar mass of NaCl = 58.44 g/mol and the molar mass of MgCl_{2} is 95.21 g/mol. Let the mass (g) of MgCl_{2}  in the original mixture be 'x'. Thus:

7.2007*10^-3 = (0.4015-x)/58.44 + 2x/95.21

(7.2007*10^-3)*58.44*95.21 = 95.21(0.4015-x) + 2x(58.44)

40.06505 = 38.227 -95.21x + 116.88x

40.06505 - 38.227 = -95.21x + 116.88x

1.83805 = 21.67x

x = 1.83805/21.67 = 0.0848 g

moles of MgCl_{2} = 0.0848g/95.21 g/mol = 8.909*10^-4 moles

4 0
3 years ago
When Bruce Banner tried saving his friend from a gamma bomb blast, he was hit with a large dose of gamma radiation. Following th
ivanzaharov [21]

Answer:

22

Explanation:

7 0
2 years ago
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