Answer:
<h3>The answer is 200 cm³</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass = 150 g
density = 0.75 g/cm³
We have

We have the final answer as
<h3>200 cm³</h3>
Hope this helps you
Answer:
The total pressure of three gases is 837.56 mmHg.
Explanation:
The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:
PT = PA + PB
This relationship is due to the assumption that there are no attractive forces between the gases.
In this case, the total pressure can be calculated as:
PT= 2.67 mmHg + 45.69 mmHg + 789.6 mmHg
Solving:
PT= 837.56 mmHg
<em><u>The total pressure of three gases is 837.56 mmHg.</u></em>
Answer:
8.909*10^-4 moles
Explanation:
The mixture contains MgCl
and NaCl with a total mass of 0.4015 g. The mass of precipitate AgCl(aq) is 1.032 g and it has a molar mass of 143.32 g/mol. Therefore, the moles of the precipitate is:
n = 1.032/143.32 = 7.2007*10^-3 moles
Molar mass of NaCl = 58.44 g/mol and the molar mass of MgCl
is 95.21 g/mol. Let the mass (g) of MgCl
in the original mixture be 'x'. Thus:
7.2007*10^-3 = (0.4015-x)/58.44 + 2x/95.21
(7.2007*10^-3)*58.44*95.21 = 95.21(0.4015-x) + 2x(58.44)
40.06505 = 38.227 -95.21x + 116.88x
40.06505 - 38.227 = -95.21x + 116.88x
1.83805 = 21.67x
x = 1.83805/21.67 = 0.0848 g
moles of MgCl
= 0.0848g/95.21 g/mol = 8.909*10^-4 moles