A. Mass of the unknown gas.
The mass of the unknown gas is calculated by subtracting the weight of the empty flask from the mass when there was air in it.
m = 126.593 g - 125.623 g
Simplifying,
m = 0.97 grams
b. Molar mass of the gas
The molar mass of the gas is calculated by the ideal gas law.
PV = (m/M)RT
where P is pressure,V is volume, m is the mass, M is the molar mass, R is the universal gas constant, and T is temperature. Substituting the known values to the equation,
(733 mmHg/760 mmHg/atm)(0.20 L) = (0.97 g/M)(0.0821 L.atm/molK)(99 + 273.15 K)
The value of M in the equation is 153.64 g/mol.
<em>Answer: 153.64 g/mol</em>
Answer:
bottom right top left fig
Answer:
Kilogram
Explanation:
The metric system is the Kilogram, meter, second system. These are fundamental quantities of the metric system.
Kilogram, the unit of mass always carries the prefix 'kilo' in its SI unit. Kilogram is the SI unit of mass. Hence, the fundamental unit on the metric system that always has a prefix in front of it is kilogram.
Answer:
0.091 mol/L
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity ( unit = mol / L or M )
V = volume of solution in liter ( unit = L ),
n = moles of solute ( unit = mol ),
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the data of the question , it is given that ,
w = 1.5 g
V = 220 mL
Since ,
1 mL = 1/1000L
V = 0.220 L
As we known , the mass of bleach NaOCl is ,
m = 74.44 g/mol
from the above equation , moles can be calculated as -
n = w / m
n = 1.5g / 74.44 g/mol
n = 0.0201 mol
Molarity of the solution is calculated as ,
M = n / V
M = 0.0201 mol / 0.220 L
M = 0.091 mol/L
