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Yuki888 [10]
3 years ago
13

Two pith balls hang side by side close to each other without touching as shown in the figure below. They are both neutral to beg

in with.
a.A plastic rod is rubbed with wool. Describe as negative, positive or neutral the total (net) charge of a system consisting of the rod and the cloth. Explain your reasoning.

b.A student touches sphere A briefly with the rod and then removes it. Then he brings the rod close to sphere A but does not touch it. What will happen to A? Explain your reasoning.

c.What is the charge state of the system consisting of the rod and wool now? Explain your reasoning.

d.Now sphere B is brought very close to A but does not touch it. What will happen to the spheres? Explain your reasoning.

e.Now the student touches sphere B with the same charged rod as above. What will happen to spheres A and B afterwards? Again, the spheres are close to each other but do not touch. Explain your reasoning.

f.What is the charge state of the system consisting of the rod and both spheres? Explain your reasoning.

g.Sphere B is now discharged. Then it is touched by a glass rod that was rubbed with silk. Now both spheres are brought close to each other. What will happen to the spheres now? Explain your reasoning.

h.Both spheres are now moved a bit further apart. What will happen to them now? Explain your reasoning.
Physics
1 answer:
Mila [183]3 years ago
4 0

a)

When a plastic rod is rubbed with wool, charging by friction occurs.

This is one of the three mechanisms of charging an object: in this particular case, as the rod is rubbed with the wool, electrons jump from the wool to the rod.

As a result, the plastic rod will remain with an excess of electrons (negative charge), while the wool will remain with a lack of electrons (positive charge).

However, the number of electrons gained by the rod is equal to the number of electrons given off by the wool: therefore, the total net charge of the system rod + cloth has not changed.

b)

When the rod touches sphere A, some electrons are transferred from the rod to the sphere (this method of charging is called charging by conduction).

Then, the sphere A will also remain negatively charged, as well as the plastic rod.

Later, the rod is brought close to sphere A without touching it: here, the electrons in the rod repel the electrons in the sphere (like charges repel each other), so the rod and the sphere will repel each other.

c)

Before part b), the negative charge on the plastic rod was equal to the positive charge on the wool.

After part b), the plastic rod has given off part of its electrons to sphere A. As a result, the negative charge on the plastic rod will be now less than the positive charge on the wool.

Therefore, the net charge of the rod + wool system will now be positive.

d)

The electrostatic force between two charged object is:

- Attractive if the charges on the objects have opposite sign

- Repulsive if the charges on the objects have same sign

Since sphere A is charged negatively, when it is brought close to sphere B, the electrons in sphere B will be attracted on the opposite side relative to sphere A, while the positive charges will migrate close to sphere A. Therefore, the two spheres will attract each other, since opposite charges attract each other.

e)

When the plastic rod (which is negatively charged) touches sphere B, some electrons are transferred to sphere B (charging by induction). As a result, charge B will also be negatively charged now, as it has an excess of electrons.

At the same time, sphere A is also negatively charged. Therefore, as like charges repel each other, this means that the two spheres will now repel each other.

f)

The net charge of the rod and the two spheres is negative.

In fact, the electrons given off by the rod to the two spheres were initially on the rod itself: this means that the total net charge of the rod + 2 spheres is equal to the net charge on the rod before the process.

Since the net charge on the rod before the process was negative, then the net charge of the system consisting of the rod + 2 spheres must be negative as well.

g)

When a glass rod is rubbed with silk, charging by friction occurs, similar to part a). However in this case, the glass rod gives off electrons to the silk: therefore, the glass rod remains positively charged.

Later, the glass rod touches sphere B: as a result, positive charge is transferred from the rod to sphere B, so sphere B will remain positively charged.

In the meantime, sphere A is negatively charged: since opposite charges attract each other, this means that now sphere A and sphere B will attract each other.

h)

When the two spheres are moved a bit further apart, the attractive force between them decreases a bit. In fact, the electrostatic force between two charged objects is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the  charges on the two objects

r is the separation between the objects

As we can see, the force is inversely proportional to the square of the distance: therefore, if the separation between the spheres increases, the force will decrease.

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Two blocks are connected by a massless rope that passes over a 1 kg pulley with a radius of 12 cm. The rope moves over the pulle
tangare [24]

Answer:

F=1.159

Explanation:

From the question we are told that:

Mass of pulley M=1kg

Radius r=12cm

Mass of block A M_a=2.1kg

Mass of block B m_b=4.1kg

Spring constant\mu= 358 J/m2

Generally the equation for Torque is mathematically given by

Since \sumF=ma

At mass A

 T_2-f_3=2.1a

At mass B

 4.8-T_1=4.1a

At  Pulley

 R(T_1-T_2)=\frac{1*1*R^2}{2}\frac{a}{R}

 R(T_1-T_2)=0.55a

Therefore the equation for total force F

At mass A+At mass B+At  Pulley

 (T_2-f_3+4.8-T_1+R(T_1-T_2)=2.1a+4.1a+0.55a

 (T_2-f_3+4.8-T_1+R(T_1-T_2)=2.7a+4.8a+0.55a

 -f_3+4.1=6.75a

 -f_3=6.75a+4.8

Since From above equation

M_{eff}=6.7kg

Therefore

T=2\pi \sqrt{{\frac{M_{eff}}{k}}

T=2\pi \sqrt{{\frac{6.75}{\mu}}

T=0.862s

Generally the equation for frequency is mathematically given by

F=\frac{1}{T} \\F=\frac{1}{0.862}

F=1.159

3 0
3 years ago
A car moving at some speed hits the brakes and skids to a stop after 13 m on a level road. If the coefficient of friction for th
vesna_86 [32]

Answer:

12.974 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s²

\mu = Coefficient of friction =0.66

a = Acceleration = \mu g

v^2-u^2=2as\\\Rightarrow -u^2=2\mu gs-v^2\\\Rightarrow u=\sqrt{v^2-2\mu gs}\\\Rightarrow u=\sqrt{0^2-2\times -(9.81\times 0.66)\times 13}\\\Rightarrow u=12.974\ m/s

Car's original speed before braking was 12.974 m/s

6 0
4 years ago
A child is sliding on a sled at 1.3 m/s to the right. You stop the sled by pushing on it for 0.80 s in a direction opposite to i
Shalnov [3]

Answer:

find acceleration first

a = vf - vi / t

a = 0  - 1.5 / 0.5s   (vf is zero)

a = -3 (negative sign indicates that acceleration is decreasing)

so F=ma

    F = 35 x -3

   F = -105 N (here negative sign indicates that u have to apply a force opposite to the boy's direction i.e from the left or towards the right)

Explanation:

3 0
4 years ago
An object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second. What distance
Tcecarenko [31]

Answer: 90m

Explanation:

Use Equation for distance:

S=a*t²/2

use eqation for acceleraton a=(Vf-Vs)/t

Vs- starting speed

Vf - final speed

a-accelaration

---------------------------------

a=5m/s²

Vs=0m/s

Vf=30m/s

use

a=(Vf-Vs)/t

to find time

t=(Vf-Vs)/a

t=30m/s/5m/s²

t=6s

Now calculate distance that object travel using:

S=(a*t²)72

s=(5m/s²*(6s)²)/2

S=90m

4 0
3 years ago
Read 2 more answers
What would be the mass of a sample containing 0.7 mol of pure tungsten?. . 0.04 g. . 51.8 g. . 128.7 g. . 262.6 g.
mojhsa [17]
There are several information's of immense importance already given in the question. The answer to the question can be easily determined using those available information's. 

Mr of pure tungsten = 183.84
Mass of tungsten = Mole * Mr
                             = 0.7 * 183.84
                             = 128.7 gm
From the above deduction, it can be concluded that the correct option among all the options that are given in the question is the third option or the penultimate option.
4 0
3 years ago
Read 2 more answers
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