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Sergeeva-Olga [200]
2 years ago
6

Astronauts are trained for take-off in a high-speed centrifuge of 4.7 m radius that spins in the horizontal plane.

Physics
1 answer:
Leokris [45]2 years ago
8 0

Answer:

a) 1.94 \frac{rad}{s}

b) 9.12\frac{m}{s}

c) Towards the center of the centrifuge

Explanation:

a)

Becuse the centrifuge rotates in circular motion, there's an angular acceleration tha simulates high gravity accelerations

a_{rad}=\omega r^{2}

with r the radius and ω the amgular velocity, in or case a_rad=3.5g so:

3.5g=\omega r^{2} and g=9.8\frac{m}{s^{2}}

solving for ω:

\omega=\frac{3.5g}{r^2}=\frac{3.5*9.8}{4.2^2}

\omega = 1.94 \frac{rad}{s}

b) Linear speed (v) and angular speed are related by:

v=\omega r =(1.94)(4.7)

v= 9.12\frac{m}{s}

c) The apparent weigth is pointing towards the center of the circle, becuse angular acceleration is pointing in that direction.

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Answer:

The excess charge on earth's surface was calculated to be 4.56 × 10⁵ C

Explanation:

Using the formula for an electric field;

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k = 1/(4πε₀) = 8.99 × 10⁹ Nm²/C²

E = 100N/C

r = radius of the earth = 6400 km = 6400000m

Q = Er²/k = 100 × (6400000)²/(8.99 × 10⁹)

Q = 455617.4 C = 4.56 × 10⁵ C

Hope this helps!!!

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A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that ti
Sergeeva-Olga [200]

Acceleration  =  (change in speed)  /  (time for the change)

                       =      (49 m/s)   /   (5 seconds)

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In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A r
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Answer:

570 N

Explanation:

Draw a free body diagram on the rider.  There are three forces: tension force 15° below the horizontal, drag force 30° above the horizontal, and weight downwards.

The rider is moving at constant speed, so acceleration is 0.

Sum of the forces in the x direction:

∑F = ma

F cos 30° - T cos 15° = 0

F = T cos 15° / cos 30°

Sum of the forces in the y direction:

∑F = ma

F sin 30° - W - T sin 15° = 0

W = F sin 30° - T sin 15°

Substituting:

W = (T cos 15° / cos 30°) sin 30° - T sin 15°

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The rider weighs 570 N (which is about the same as 130 lb).

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