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djyliett [7]
2 years ago
6

Why do you start with the least polar solvent/solvent mixture and progress to increasing polar solvent/solvent mixtures when elu

ting the ferrocene compounds from the column rather than starting with more polar solvent system and progressing to less polar solvents
Chemistry
1 answer:
gregori [183]2 years ago
4 0

Explanation:

Generally in normal phase column, inside the column silica gel present is in normal phase and it strongly reacts or combine with more polar ferrocene compounds. Whereas, less polar ferrocene compounds weakly interact with this silica gel.  

Hence, on starting with least polar solvent or solvent-mixture the less polar ferrocene compounds will tend to elute first of all because these will weakly interact with the silica gel. Therefore, readily able to move away from the gel.

On increasing the polarity of solvent or solvent mixture, more polar ferrocene compounds will start to elute first. As a result, on changing the solvent polarity we can (from least to more polar) it is possible to get pure products.

But if we start with more polar solvent at first then almost all of the ferrocene compounds will elute leading to poor separation from the column due to which you will end up having a mixture of ferrocene compounds.

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Which is smaller 25 mm or 25cm
umka21 [38]

Answer:

25 mm is smaller.

5 0
3 years ago
How many grams (g) are in 0.250 moles of copper?
MissTica

Answer:

15.89grams

Explanation:

The mass of a substance can be calculated from it's mole value by using the formula:

mole = mass/molar mass

According to this question, there are 0.250 moles of copper. Hence, the mass of copper can be calculated as follows:

Molar mass of Cu = 63.55g/mol

0.250 = mass/63.55

mass = 0.250 × 63.55

mass = 15.8875

Mass of Cu in 0.250mol is 15.89grams.

5 0
2 years ago
Chlorine has a atomic number of 17. It often forms an ion by gaining 1 electron. What would it's charge be?
kvasek [131]

Answer:

The charge would be -1.

Explanation:

5 0
2 years ago
A solution contains 0.021 M Cl and 0.017 M I. A solution containing copper (I) ions is added to selectively precipitate one of t
lidiya [134]

<u>Answer:</u> Copper (I) iodide will precipitate first.

<u>Explanation:</u>

We are given:

K_{sp} of CuCl = 1.0\times 10^{-6}

K_{sp} of CuI = 5.1\times 10^{-12}

Concentration of Cl^-\text{ ion}=0.021M

Concentration of I^-\text{ ion}=0.017M

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

  • <u>For CuCl:</u>

K_{sp}=[Cu^+][Cl^-]

Putting values in above equation, we get:

1.0\times 10^{-6}=[Cu^+]\times 0.021

[Cu^+]=\frac{1.0\times 10^{-6}}{0.021}=4.76\times 10^{-5}M

Concentration of copper (I) ion = 4.76\times 10^{-5}M

  • <u>For CuI:</u>

K_{sp}=[Cu^+][I^-]

Putting values in above equation, we get:

5.1\times 10^{-12}=[Cu^+]\times 0.017

[Cu^+]=\frac{5.1\times 10^{-12}}{0.017}=3.00\times 10^{-10}M

Concentration of copper (I) ion = 3.00\times 10^{-10}M

For the precipitation of copper (I) ions, we need less concentration of copper (I) ions. So, copper (I) iodide will precipitate first.

7 0
3 years ago
HELP THIS HAS TO BE TURNED IN IN AN HOUR
svetlana [45]

Answer:

B

Explanation:

6 0
2 years ago
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