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crimeas [40]
3 years ago
12

List three ways in which metals and nonmetals differ.

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Explanation:

<u>The point of difference between metals and non metals are as follows - </u>

Metals -

Metals are malleable in nature , so can be beaten into thin sheets .

Non - metals -

Non - metals are brittle in nature , so when beaten , it can be powdered .

Metals -

Metals have one to three electrons in the very outer most shell .

Non - metals -  

Non - metals have four to eight electrons in the very outer most shell .

Metals -

Metals are lustrous in appearance .

Non - metals -

Non - metals re not lustrous in appearance .

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Two balloons have a negative charge. What happens when they are brought near each other?
Salsk061 [2.6K]

Answer:

They will attract each other because opposite charges attract

Explanation:

7 0
4 years ago
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What is the systematic name for the following structure, specifying cis-/trans-?
Andrej [43]

Answer:

cis-3,4-dimethyl-3-hexene

Explanation: since the substituents are on same side, it call cis. Followed by the name

6 0
3 years ago
Lons form because the loss of one or more electrons makes
ruslelena [56]

This statement lons form because the loss of one or more electrons makes them less stable than their corresponding atoms; this state requires more energy to maintain is FALSE.

  • An ion forms when an atom loses or gains one more electrons.
  • This loss or gain of electrons causes the ion to gain the stable octet configuration.
  • This stable octet configuration requires less energy to maintain than the corresponding atom.

So, since the stable octet configuration of the ion requires less energy than the corresponding atom, the statement is false.

So, the statement lons form because the loss of one or more electrons makes them less stable than their corresponding atoms; this state requires more energy to maintain is FALSE.

Learn more about ions here:

brainly.com/question/3631272

7 0
3 years ago
Balance the following redox equations by the half-reaction method:
frozen [14]

Answer:

a)  Mn^2+ + 2OH- + H2O2 → MnO2 + 2H2O

b) 2Bi(OH)3 + 3SnO2^2-  → 2Bi + 3SnO3^2- + 3H2O

c) Cr2O7^2- + 3C2O4^2- + 14H+ → 2Cr^3+ +7H2O + 6CO2

d) 2ClO3- + 2Cl- + 4H+   → Cl2 + 2H2O +2ClO2

e) 5 BiO3^- + 14 H+ + 2Mn^2+  → 5Bi^3+ + 7H2O + 2MnO4^-

Explanation:

<em>(a) Mn2 + H2O2 → MnO2 + H2O (in basic solution)</em>

Step 1: The half reactions

Oxidation: Mn2+ + 4OH- → MnO2 + 2H2O + 2e-

Reduction: H2O2 + 2e- + 2H2O  →  2H2O + 2OH-

Step 2: Sum of both half reactions

Mn2+ + 4OH- + H2O2  → MnO2 + 2H2O  + 2OH-

Step 3: the netto reaction

Mn^2+ + 2OH- + H2O2 → MnO2 + 2H2O

<em>(b) Bi(OH)3 + SnO2^2-  → SnO3^2- + Bi (in basic solution)</em>

Step 1: The half reactions

Reduction:  Bi(OH)3 + 3e-  → Bi

Oxidation : Sno2^2-  → SnO3^2- +2e-

Step 2: Balance the half reactions

2* (Bi(OH)3 + 3e-  → Bi + 3OH-)

3* (Sno2^2- +2OH-  → SnO3^2- +2e- + H2O)

Step 3: The netto reaction

2Bi(OH)3 + 3SnO2^2-  → 2Bi + 3SnO3^2- + 3H2O

<em>(c) Cr2O7^2- + C2O4^2- → Cr^3+ + CO2 (in acidic solution)</em>

Step 1: The half reactions

Reduction: Cr2O7^2- + 6e-  → 2Cr+

Oxidation : C2O4^2- → 2CO2 + 2e-

Step 2: Balance the half reactions

Cr2O7^2- + 6e-  +14H+  → 2Cr+ +7H2O

3*(C2O4^2- → 2CO2 + 2e-)

Step 3: The netto reaction

Cr2O7^2- + 3C2O4^2- + 14H+ → 2Cr^3+ +7H2O + 6CO2

<em>(d) ClO3^- + Cl^− </em>→<em> Cl^2 + ClO^2 (in acidic solution)</em>

Step 1: The half reactions

Reduction: 2 ClO3^- + 10e- → Cl2

                      ClO3^- + e- → ClO2

 2 Cl- + 2ClO3^- +8e- →2Cl2

Oxidation: 2Cl- → Cl2 + 2e-

                   Cl- → ClO2 + 5e-

Cl- +ClO3^- → 2ClO2 + 4e-

Step 2: Balance the reactions

2Cl- + 2ClO3^- + 8e- + 12H+ → 2Cl2 + 6H2O

2* (Cl- + ClO3^- + H2O → 2ClO2 + 4e- + 2 H+)

Step 3: The netto reaction

2ClO3^- + 2Cl- + 4H+   → Cl2 + 2H2O +2ClO2

<em>(e) Mn^2 + BiO3^− </em>→<em> Bi^3 + MnO^4− (in acidic solution)</em>

Step 1: The half reactions

Reduction: BiO3^- + 2e- → Bi^3+

Oxidation : Mn^2+ → MnO4^- +5e-

Step 2: Balanced the reactions

5* ( BiO3^- + 2e- + 6H+ → Bi^3+ + 3H2O)

2* ( Mn^2+ + 4H2O →MnO4^- + 5e- + 8H+)

Step 3: The netto reaction

5 BiO3^- + 14 H+ + 2Mn^2+  → 5Bi^3+ + 7H2O + 2MnO4^-

6 0
4 years ago
(I will give a Brainliest)
gogolik [260]
The particles would be more scattered out as those three factors increase.
3 0
3 years ago
Read 2 more answers
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