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Minchanka [31]
4 years ago
11

Two balloons have a negative charge. What happens when they are brought near each other?

Chemistry
2 answers:
harina [27]4 years ago
8 0

Answer : The correct option is, They repel each other.

Explanation :

There are two types of charges which are positive and negative charge.

There are two conditions:

When the two bodies have like charges that means positive-positive or negative-negative then they repel each other.

When the two bodies have unlike charges that means positive-negative then they attract each other.

As per question, when two balloons have a negative charge that means they have like charges. So, they repel each other.

Hence, the correct option is, They repel each other.

Salsk061 [2.6K]4 years ago
7 0

Answer:

They will attract each other because opposite charges attract

Explanation:

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Consider the molecules: scl2, f2, cs2, cf4, and brcl. select the choice where the bonds of the molecules are arranged in order o
elena-s [515]

The polarity of a bond depends on the difference in electronegativities of the atoms involved in bonding. Greater this difference, greater is the polarity

1) In SCl2 we have the S-Cl bond

Electronegativity values: S = 2.5, Cl = 3

Difference = 3.0 -2.5 = 0.5

2) In F2 we have the F-F bond

Electronegativity value: F = 4.0

Difference = 4.0-4.0 = 0

3) In CS2 we have the C-S bond

Electronegativity value: C = 2.5, S = 2.5

Difference = 2.5 -2.5 = 0

4) In CF4 we have the C-F bond

Electronegativity values: C = 2.5, F = 4.0

Difference = 4.0 -2.5 = 1.5

5) In BrCl we have the Br-Cl bond

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Difference = 3.0 -2.8 = 0.2

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F2 = CS2 < BrCl < SCl2 < CF4

5 0
3 years ago
What is the formula for the compound by calcium ions and chloride ions?
dimaraw [331]
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4 years ago
A solution of NaOH is titrated with H2SO4. It is found that 20.05 mL of 0.3564 M H2SO4 solution is equivalent to 43.42 mL of NaO
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Answer : The concentration of NaOH is, 0.336 M

Explanation:

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.3564M\\V_1=20.05mL\\n_2=1\\M_2=?\\V_2=43.42mL

Putting values in above equation, we get:

2\times 0.3564M\times 20.05mL=1\times M_2\times 43.42mL

M_2=0.336M

Thus, the concentration of NaOH is, 0.336 M

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3 years ago
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