Filtration
distillation
crystallization
chromatography
Answer:
B
Explanation:
962,320 J
230 nutritional Calories in Joules is 962,320 J
Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate
in order to prepare a 0.452 m solution
Explanation:
Molality : It is defined as the number of moles of solute present per kg of solvent
Formula used :

where,
n= moles of solute
Moles of
= weight of the solvent in g = ?


Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate
in order to prepare a 0.452 m solution
Zn(s) + 2HCl(aq) = ZnCl₂(aq) + H₂(g)
zinc + hydrochloric acid = zinc chloride + hydrogen
(a)- Time
(b)- Heat produced(i guess)
(c)- Material
this is what I think, hope it helps