Answer:
81 °C
Explanation:
This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:
q = heat added/released by a sample
m = mass of sample
c=specific heat of sample
ΔT = change in temperature
from here we can rearrange the equation to state:
q/(mc) = ΔT
1200J/((20.0g)(4.2J/g•°C)) = ΔT
14°C = ΔT
If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.
The first example of diffusion is smoking a cigarette when u light it it spreads through the air.
The second example is lighting a candle in a room it the smoke spreads through the air.
Smoke can be very bad for the air and the people around because it can cause many problems with your breathing.
Answer:
Explanation:
Radioactive decay follows the equation:
Ln [A] = -kt + ln [A]₀
<em>Where [A] is amount of isotope after time t: Our incognite,</em>
<em>k is rate constant: ln 2 / Half-life = 0.0231 years⁻¹</em>
<em>t are 60 years</em>
<em>[A]₀ is initial amount of isotope: 1.0g</em>
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Replacing:
Ln [A] = -kt + ln [A]₀
Ln [A] = -0.0231 years⁻¹*60 years + ln 1.0g
ln [A] = -1.386
[A] = 0.25g
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