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a_sh-v [17]
2 years ago
10

Suppose much of an old forest will be used for farmland. A certain portion of the land will be set aside as wildlife habitat. Yo

u are asked to chose between the two plans outlined in A and B. The green areas represent the proposed reserve areas. Which plan will you recommend? Explain your reasoning.
Chemistry
1 answer:
WITCHER [35]2 years ago
7 0

Answer:

A certain portion of the land will be set aside as wildlife habitat

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Someone answer these both for me
Julli [10]

Answer:

a b

Explanation:

I think so take it with a grain of salt

4 0
3 years ago
How is a pair of molecular orbitals formed?
Montano1993 [528]
When two atoms combine, the overlap of their atomic orbitals produces molecular orbitals. 
3 0
3 years ago
Read 2 more answers
What is the significance of the Roman Numeral when naming binary ionic compounds?
serious [3.7K]

Answer:

Roman numbers are oxidation state of the metals

Because some elements of metals show more than one oxidation state like iron Fe2+ in ferrous and Fe3+ in ferric.

Explanation:

8 0
3 years ago
What fraction of the original atoms of the radioactive sample will remain after the given number of half-lives has passed?
meriva

Answer:

1/8

Explanation:

\frac{1}{ {2}^{3} }  =  \frac{1}{8}

Mark brainliest please

5 0
2 years ago
If 100 mg of ferrocene is reacted with 75 mg of anhydrous aluminum chloride and 40 microliters of acetyl chloride and 100 mg of
Alex_Xolod [135]

Answer:

81.3 %

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For ferrocene:-

Mass of ferrocene = 100 mg = 0.1 g

Molar mass of ferrocene = 186.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{0.1\ g}{186.04\ g/mol}

Moles\ of\ ferrocene= 0.0005375\ mol

For acetyl chloride:-

Volume = 40 microliters = 0.04 mL

Density = 1.1 g / mL

Density is defined as:-

\rho=\frac{Mass}{Volume}

or,  

Mass={\rho}\times Volume=1.1\times 0.04\ g=0.044 g

Mass of acetyl chloride = 0.044 g

Molar mass of acetyl chloride = 78.49 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{0.044\ g}{78.49\ g/mol}

Moles\ of\ acetyl\ chloride= 0.0005606\ mol

As per the reaction stoichiometry, one mole of ferrocene reacts with one mole of acetyl chloride to give one mole of monoacetylferrocene

Limiting reagent is the one which is present in small amount. Thus, ferrocene is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

one mole of ferrocene on reaction forms one mole of monoacetylferrocene

0.0005375 mole of ferrocene on reaction forms  0.0005375 mole of monoacetylferrocene

Moles of product formed =  0.0005375 moles

Molar mass of monoacetylferrocene = 228.07 g/mole

Mass of monoacetylferrocene produced = Moles*molecular weight = 0.0005375*228.07 g = 0.123 grams = 123 mg

Given experimental yield = 100 mg

<u>% yield = (Experimental yield / Theoretical yield) × 100 = (100/ 123) × 100 = 81.3 %</u>

5 0
3 years ago
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