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3 years ago

What is an example of a negative incentive for producers

1 answer:

7 0

An example of a negative incentive for producers is the sharp increase in production costs. Producers are the one who manage the production costs and even the production budget. Anything that relates the production department is entitled to the management of production producers.

There is what we called positive and negative incentives and both of these can affect consumers and producers. Positive incentives are those situations which will give a certain outcome that will benefit the producers, for example, during the peak season there will be a high demand of products, and this gives the chance of producers to demand a higher price from the consumers, in this situation, there will be a big chance of increase sales. A sharp increase in production costs is a loss for the producers. If there will be an increase in production costs, the budget will be greatly affective and even though it is not a peak season, there’s a big chance also to increase prices which we know, consumers are not fond of.

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A train travels 85 kilometers in 5 hours, and then 63 kilometers in 5 hours what is its average speed?

Lesechka [4]

We know average speed =total distance/time taken
So avg speed=(85+63)/(5+5)=14.8km/hr

3 0

3 years ago

On a straight, level, two-lane road, two cars moving in opposite directions approach and pass each other. Car A is in the eastbo

ludmilkaskok [199]

Answer:

a) 42 m/s, positive direction (to the east), b) 42 m/s, negative direction (to the west).

Explanation:

a) Let consider that Car A is moving at positive direction. Then, the relative velocity of Car A as seen by the driver of Car B is:

$\vec v_{A/B} = \vec v_{A} - \vec v_{B}\\\vec v_{A/B} = 11 \frac{m}{s} \cdot i + 31 \frac{m}{s} \cdot i\\\vec v_{A/B} = 42 \frac{m}{s} \cdot i$

42 m/s, positive direction (to the east).

b) The relative velocity of Car B as seen by the drive of Car A is:

$\vec v_{B/A} = \vec v_{B} - \vec v_{A}\\\vec v_{B/A} = -31 \frac{m}{s} \cdot i - 11 \frac{m}{s} \cdot i\\\vec v_{B/A} = - 42 \frac{m}{s} \cdot i$

42 m/s, negative direction (to the west).

5 0

3 years ago

How deep can an object with 6360N hitting on a sponge get ???

borishaifa [10]

Answer:

The sponge must go $\dfrac{636}{m}\ \text{meter}$ deep

Explanation:

If F = 6360 N, then it is required to find how deep can an object with this force hitting on a sponge get.

We know that, F = mgh

m is mass

g is acceleration due to gravity

$h=\dfrac{F}{mg}\\\\h=\dfrac{6360}{10m}\\\\h=\dfrac{636}{m}\ \text{meter}$

So, the sponge must go $\dfrac{636}{m}\ \text{meter}$ deep.

5 0

3 years ago

State a true conclusion.

Ganezh [65]

The conclusion is; Cathy's dad has gone fishing.

<h3>What are conclusions in conditional statements?</h3>

A conditional statement is a statement with a hypothesis which is then followed by a conclusion.

A conditional statement has two parts; "if" and "then"

The hypothesis is “if,” part of a conditional statement.

The conclusion is the “then,” part of a conditional statement.

Considering the given conditional statements:

1. If it's Saturday, then Cathy's dad goes fishing.

2. If it's Saturday, then Cathy's dad goes fishing.

Since the if part is true, the conclusion will be, Cathy's dad has gone fishing.

In conclusion, a conditional statement consists of a hypothesis and a conclusion.

Learn more about conditional statements at: brainly.com/question/21170
#SPJ1

7 0

2 years ago

Its a motion phisic question but im a little confused. Help me fast please.

Alenkinab [10]

6: Short way: it cannot be 2.5, 3, or 5 because up to 5 seconds it only has positive velocity so it must be moving forwards.

Long Way: Velocity is in m / s, multiply that by time (s) to get m or displacement. From 0->5 you have a triangle under the curve, (1/2)(5)(20) = 50 meters displaced positive, you need to then look when velocity is under the curve and use a similar equation to solve for the area but make the answer negative. Find the point where it equals -50 and that is where it will have returned.

Answer to 6: B

7. I cannot see the problem enough to answer this. Just know if the line is above 0 velocity is positive so it is moving the direction it started, when it goes below 0 velocity is negative so it is moving opposite direction it started.

8. Accelration is change in velocity. Whatever the slope of the velocity graph is acceleration. At t=8 the slope is 0 because it is not going up or down.

Answer to 8: A

3 0

3 years ago