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Nostrana [21]
4 years ago
7

How many elements are in CoH1206?

Physics
2 answers:
aliina [53]4 years ago
4 0

Answer:

19 elements

Explanation:

1 carbon + 12 hydrogen + 6 oxygen = 19

TEA [102]4 years ago
3 0

Answer:

There are <em>3</em><em> </em>elements present in this compound.

Explanation:

The elements present in <em>C</em><em>o</em><em>b</em><em>a</em><em>l</em><em>t</em><em> </em><em>H</em><em>e</em><em>x</em><em>a</em><em>h</em><em>y</em><em>d</em><em>r</em><em>a</em><em>t</em><em>e</em><em> </em>, is <u><em>C</em><em>o</em><em>b</em><em>a</em><em>l</em><em>t</em></u><em> </em><em>,</em><em> </em><u><em>H</em><em>y</em><em>d</em><em>r</em><em>o</em><em>g</em><em>e</em><em>n</em></u><em> </em>and <u><em>O</em><em>x</em><em>y</em><em>g</em><em>e</em><em>n</em></u><em> </em><em>.</em>

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A trough in a transverse wave corresponds to a ________ <br> In a longitudinal wave.
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During a game of tug-of-war, one team exerts a force of 3,500 N to the left. The other team exerts a force of 3,800 N to the rig
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A wave with an amplitude of 9.3 mm is traveling along a string whose linear mass density is 230 g/m and whose tension is 65 N. I
dsp73

Answer:

The rate of transfer of energy is equal to 23.76W or 23.76J/s as may be required both forms are correct. The physical quantities needed to calculate the rate of energy transfer are the linear mass density or mass per unit length, tension force, amplitude, angular frequency( which is equal to 2pi •f )

Explanation:

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3 0
3 years ago
Suppose a 65 kg person stands at the edge of a 6.5 m diameter merry-go-round turntable that is mounted on frictionless bearings
Hatshy [7]

Answer:0.316 rad/s

Explanation:

Given

mass of Person m=65 kg

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diameter of turntable d=6.5 m

moment of Inertia of the table I_0=1850 kg-m^2

Moment of inertia of Person I

I=mr^2=65\times (\frac{6.5}{2})^2

I=686.56 kg-m^2

initial angular velocity \omega _1=\frac{v}{r}

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Conserving Angular momentum

I\omega _1=(I+I_0)\omega _2 , where \omega _2=final\ angular\ velocity

686.56\times 1.17=(686.56+1850)\times \omega _2

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\omega _2=0.316 rad/s

4 0
3 years ago
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