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lbvjy [14]
4 years ago
9

A neutral atom possesses an number of 13 and an atomic mass of 27.three electrons are lost.from what region of the atom are they

lost?
A.Outside the atom

B.Outside the nucleus

C. inside the nucleus

D. both inside and outside the nucleus
Chemistry
1 answer:
Pavlova-9 [17]4 years ago
3 0
They are lost from valence shell (it's outermost shell of an atom).

->>> outside the atom
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Answer:

80.27%

Explanation:

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2 Fe³⁺(aq) + Sn²⁺(aq) ⇒ 2Fe²⁺(aq) + Sn⁴⁺(aq)

First, we have to calculate the moles of Sn²⁺ that react.

\frac{0.1015molSn^{2+} }{1L} .13.28 \times 10^{-3} L=1.348\times 10^{-3}molSn^{2+}

We also know the following relations:

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Then, for 1.348 × 10⁻3 moles of Sn²⁺:

1.348\times 10^{-3}molSn^{2+}.\frac{2molFe^{3+} }{1molSn^{2+} } .\frac{1molFe}{1molFe^{3+} } .\frac{55.84gFe}{1molFe} =0.1505gFe

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5 0
4 years ago
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Answer:

C. Cs < K < P

Explanation:

Electronegativity is the basically the tendency of an atom to attract electrons. The pauling scale is used to quantify electronegativity, the most electronegative element; fluorine has a value of 4.0 and francium, the least electronegative element has a value of 0.7

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