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lbvjy [14]
4 years ago
9

A neutral atom possesses an number of 13 and an atomic mass of 27.three electrons are lost.from what region of the atom are they

lost?
A.Outside the atom

B.Outside the nucleus

C. inside the nucleus

D. both inside and outside the nucleus
Chemistry
1 answer:
Pavlova-9 [17]4 years ago
3 0
They are lost from valence shell (it's outermost shell of an atom).

->>> outside the atom
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What is neutralization ?
blagie [28]

Answer:

"a chemical reaction in which acid and a base react quantitatively with each other"

Explanation:

5 0
3 years ago
What is the velocity of a wave traveling north with a frequency of 75 hertz and a wavelength of
Vanyuwa [196]

Answer:

v = 450 m/s

Explanation:

Given data:

Frequency = 75 Hz

Wavelength = 6 m

Velocity = ?

Solution:

Velocity is the product of frequency and wavelength.

v = f × λ

v = 75 Hz ×  6 m

Hz = s⁻¹

v = 75  s⁻¹  ×  6 m

v = 450 m/s

3 0
3 years ago
A gas sample with a volume of 1,500 cm® is heated from -65 °C to 75 °C. Assuming the
djverab [1.8K]

Answer:

V₂ = 2509.62 cm³

Explanation:

Given data:

Initial volume = 1500 cm³

Initial temperature = -65°C (-65 + 273 = 208 K)

Final temperature = 75°C ( 75 +273 = 348 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1500 cm³ × 348 K / 208 k

V₂ = 522000 cm³.K / 208 k

V₂ = 2509.62 cm³

7 0
3 years ago
Which direction will the following reaction (in a 5.0 L flask) proceed if the pressure of CO_2(g) is 1.0 atm? CaCO_3(s) rightarr
storchak [24]

Answer:

d. To the left because Q > K_p

Explanation:

Hello,

In this case, for the given reaction:

CaCO_3(s) \rightarrow CaO(s) + CO_2(g)

The pressure-based equilibrium expression is:

Kp=p_{CO_2}

In such a way, since Kp is given we rather compute the reaction quotient at the specificed pressure of carbon dioxide as shown below:

Q=p_{CO2}=1.0

Therefore, since Q>Kp we can see that there are more products than reactants, which means that the reaction must shift leftwards towards the reactants in order to reestablish equilibrium, thus, answer is d. To the left because Q > Kp.

Regards.

6 0
3 years ago
how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate
Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})

= 95.7gNaClO_3

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate  and then the grams are converted to kg.

95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0
3 years ago
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