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2 years ago

Match each type of learning to the correct definition

Chemistry

2 answers:

Radda [10]2 years ago

7 0

Answer:

Insight learning=2 one

conditioning=4th one

Imprinting=1st one

Trial-and-error learning=3rd one

(If urs is not in the same order here is the written one)

Insight learning-the process of using prior knowledge to solve a problem

Conditioning-the process is associating a stimulus with a good or bad outcome

Imprinting-a bond an individual or object shortly after birth or hatching

Trial-and-error learning-the process of performing a behavior more and more skillfully.

Explanation: hope it helps got it right on edu 2021

pishuonlain [190]2 years ago

3 0

Answer:

conditioning-the process of associating a stimulus with a good or bad outcome.

trial-and-error learning-the process of performing a behavior more and more skillfully.

insight learning-the process of using prior knowledge to solve a problem.

imprinting-a bond to an indivisual or object shortly after birth or hatching.

Explanation:

Did this assignment.

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A teacher makes the following statement.

melamori03 [73]

The correct answer among the choices given is the first option.The teacher most likely is talking about distillation of a mixture. Distillation is a unit operation that separates component substances from a liquid mixture which is shown by the teacher. Also, the most common purifying technique in the production of gasoline is by this process.

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2 years ago

Read 2 more answers

What does the Atomic Number tell you? the amounr of electronstprorons

tankabanditka [31]

Answer

Atomic number or proton number tells us the number of protons found in the nucleus of every atom of that element

Explanation:

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3 years ago

Suppose of potassium iodide is dissolved in of a aqueous solution of silver nitrate. Calculate the final molarity of iodide anio

Sholpan [36]

The given question is incomplete, the complete question is:

Suppose 1.27 g of potassium iodide is dissolved in 100. mL of a 44.0 m M aqueous solution of silver nitrate. Calculate the final molarity of iodide anion in the solution. You can assume the volume of the solution doesn't change when the potassium iodide is dissolved in it. Round your answer to 3 significant digits.

Answer:

The correct answer is 0.0325 M.

Explanation:

The mass of potassium iodide or KI mentioned in the question is 1.27 grams, the molar mass of KI is 166 g/mol. The formula for determining the no of moles of the substance is mass/molar mass. Thus, the moles of KI in 1.27 grams will be,

= 1.27g / 166 g/mol = 0.00765 moles.

KI = K⁺ + I⁻

Therefore, the moles of KI will be equivalent to moles of iodide anion, that is, 0.00765 moles.

The moles of silver nitrate or AgNo3 in the solution can be determined by using the formula, molarity (M) * volume in liters. The molarity of silver nitrate given in the question is 44 mM and the volume used is 100 ml or 100/1000 L. Now putting the values we get,

= (44 M/1000) * (100 L/1000) = 0.0044 moles

The moles of silver nitrate is equivalent to moles of silver ion, which is further equivalent to the moles of iodide ion that has taken part in precipitation = 0.0044 moles.

The moles left of I⁻ in the solution will be,

0.00765 - 0.0044 = 0.00325

Now, the final molarity of iodide ion in the solution will be,

= moles/volume in liters

= 0.00325 moles / 0.100 L = 0.0325 M

7 0

3 years ago

A solution is prepared by adding 0.10 mol of iron(III) nitrate, Fe(NO3)3, to 1.00 L of water. Which statement about the solution

MrMuchimi

Answer:

Option b is correct.

Explanation:

When $Fe(NO_3)_3$ is dissolved in water, $Fe(OH)_2$ and $HNO_3$ are formed.

$Fe(NO_3)_3\; + 3H_2O \leftrightharpoons Fe(OH)_2\; + HNO_3$

As $Fe(OH)_2$ is an weak base and $HNO_3$ is a strong acid, the resulting solution will be acidic in nature.

if K_b value is known, then pH of the solution can also be determined which will support prediction.

However, acidic and basic nature of the solution can be predicted without K_b value also.

So, among the given option, (b) is correct.

6 0

3 years ago

What else is produced during the replacement reaction of magnesium and hydrochloric acid? Mg 2HCl â†’ H2.

irina [24]

A reaction in which the chemical element of the reactant is replaced by another to produce a product is called a single replacement reaction.

In a reaction, a hydrogen, metal or halogen element can get replaced with other more reactive elements to yield products.

The reaction of magnesium and hydrochloric produces:

$\rm MgCl_{2}$

The reaction can be explained as:

The reaction between the $\rm Mg$ and $\rm HCl$ is a single displacement reaction in which the more reactive metal replaces the less reactive metal from the compound.

Magnesium metal is more reactive compared to hydrogen and hence replaces $\rm H_{2}$ from chlorine to produce:

$\rm Mg (s) + 2 \;HCl \;(aq) \rightarrow MgCl_{2} \;(aq) + H_{2} (g)$

Therefore, another product formed will be magnesium chloride.

To learn more about displacement reaction follow the link:

brainly.com/question/10557249

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2 years ago