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Evgen [1.6K]
3 years ago
13

An object in motion is usually seen moving in relation to an object that appears to

Physics
1 answer:
Norma-Jean [14]3 years ago
8 0
The answer is Stay In Place
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Cold air holds less water than warm air.<br> True<br> False
Vsevolod [243]

Answer:

The answer is for your question is :

Explanation:

True

4 0
3 years ago
(1 point) Answer the following questions about the sphere whose equation is given by x2+y2+z2−4x+4y=73. x2+y2+z2−4x+4y=73. 1. Fi
pychu [463]

Answer:

R=9.

C=(2,-2,0).

Explanation:

Lets try to find how x^2+y^2+z^2-4x+4y=73 can be written in the form of (x-a)^2+(x-b)^2+(x-c)^2=R^2, since then its radius R and center of coordinates C=(a,b,c) would be easily recognizable.

Since we have the terms -4x and +4y, they seem to have come from the terms (x-2)^2 and (y+2)^2, and we would need to take care of the extra +4 by substracting then. More explicitly:

(x-2)^2-4=x^2-4x+4-4=x^2-4x, as we had originally with the x terms

(y+2)^2-4=y^2+4y+4-4=y^2+4y, as we had originally with the y terms

Which means:

x^2-4x+y^2+4y+z^2=(x-2)^2-4+(y+2)^2-4+z^2

Or, putting all together:

(x-2)^2-4+(y+2)^2-4+z^2=73

(x-2)^2+(y+2)^2+z^2=9^2

So our radius is 9 and the center is (2,-2,0).

5 0
3 years ago
Acceleration can be found by computing the slope of a blank vs .time graph
scoundrel [369]
Velocity-time graph
5 0
3 years ago
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The cornea behaves as a thin lens of focal lengthapproximately 1.80 {\rm cm}, although this varies a bit. The material of whichi
Keith_Richards [23]

Answer:

Explanation:

  a )

from lens makers formula

\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})

f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face

putting the values

\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})

1.462 = 2 - 1 / r₂

1 / r₂ = .538

r₂ = 1.86 cm .

= 18.6 mm .

b )

object distance u = 25 cm

focal length of convex lens  f  = 1.8 cm

image distance  v   = ?

lens formula

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}

\frac{1}{v} = \frac{1}{1.8} -\frac{1}{25}

.5555 - .04

= .515

v = 1.94 cm

c )

magnification = v / u

= 1.94 / 25

= .0776

size of image = .0776 x size of object

= .0776 x 10 mm

= .776 mm

It will be a real image and it will be inverted.

 

5 0
3 years ago
Communication definition​
PtichkaEL [24]

Answer:

the imparting or exchanging of information or news.

Explanation:

4 0
3 years ago
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