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3 years ago

Acceleration can be found by computing the slope of a blank vs .time graph

Physics

2 answers:

scoundrel [369]3 years ago

5 0

Velocity-time graph

ziro4ka [17]3 years ago

4 0

Answer:

velocity

Explanation:

Acceleration is defined as the rate of change of velocity. It is vector quantity. Its SI unit is m/s^2.

The formula for the acceleration is given by

$a = \frac{v - u}{t}$

Where, v is the final velocity of the object and u is the initial velocity of the object.

As we know that in velocity time graph, velocity is on the Y axis and time is on the X axis.

Slope of a graph is given by the ratio of Y axis intersept to the X axis intersept.

So, the slope of velocity time graph gives the value of acceleration of the object.

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son4ous [18]

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3 years ago

I.Solve the following problems and answer the following questions. Show all your work and provide answers rounded off to the app

Ilia_Sergeevich [38]

The sprinter’s average acceleration is 1.98 m/s²

The given parameters;

initial velocity of the sprinter, u = 18 km/h

final velocity of the sprinter, v = 27 km/h

time of motion of the sprinter, t = 3.5 x 10⁻⁴ h

Convert the velocity of the sprinter to m/s;

$initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\$

The time of motion is seconds;

$t = 3.5 \times 10^{-4} \ h \times \frac{3600 \ s}{1 \ h} = 1.26 \ s$

The sprinter’s average acceleration is calculated as follows;

$a = \frac{v- u}{t} \\\\a = \frac{7.5 \ m/s \ - \ 5 \ m/s}{1.26 \ s} \\\\a = 1.98 \ m/s^2$

Thus, the sprinter’s average acceleration is 1.98 m/s²

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marysya [2.9K]

Answer:

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3 years ago

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ludmilkaskok [199]

Answer:

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Explanation:

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