Answer:
Your questions requires diagrams of the cell to get which one is on the left or right. However, see the attached file below
The correct answer is (d) the left half-cell will decrease in concentration; and the right half-cell will increase in concentration.
Explanation:
The concentration of the Pb2+ increases in the oxidation half cell while the concentration of the Pb2+ decreases in the reduction half cell during the reaction.
In the Left Beaker (Left half cell), their is less concentration
Pb(s) ---> Pb2+(aq) + 2 e- Concentration of Pb2+(aq) increase ; Electrons going out from this side
In the Right Beaker (right half cell), their is more concentration
Pb2+(aq) + 2 e- ---> Pb(s) Concentration of Pb2+(aq) decrease ; Electrons coming in to this side
Electrons will flow from Left to Right direction.
The enol carbon or ∝-carbon nucleophile attacks at molecular bromine in the acid-catalyzed α-bromination of a ketone
Treatment of ketones with bromine in the presence of acid will results in formation of a new C-Br bond at the alpha position. The purpose of the acid is to catalysed formation of the enol from ketone , which is active nucleophile in the reaction. This reaction is called haloform reaction which is used to identify the methyl substituted ketone in the presence of aldehyde.
learn more about ketone
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Answer:
so like Each of the five states of matter collectively made up all the "stuff" that's in the universe- — everything that takes up space and has mass is matter,and All matter is made up of atoms and in turn made up of protons and neutrons and electrons.
Explanation: hope this helps
Answer:
chlorine, fluorine, bromine, iodine, Xenon, and radon
