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Evgesh-ka [11]
2 years ago
5

What is the definition for nebula

Physics
2 answers:
spayn [35]2 years ago
7 0

The definition for nebula is : A cloud of gas and dust in outer space, visible in the night sky either as an indistinct bright patch or as a dark silhouette against other luminous matter.

maw [93]2 years ago
5 0

<em>Nebulae "plural" are huge clouds of dust and gasses in outer space. Most of the gas is made up helium and also hydrogen. Nebulae are very big and can be be many light years away.</em>

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Are forces of attraction among the particles in all mater? true or false.
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Answer:

the answer is true

Explanation:

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Irina rode her bike to work at an average speed of 16 miles per hour. It started to rain, so she got a ride home along the same
KengaRu [80]

Answer:

0.7 hours

Explanation:

From the way back, we can calculate the distance between Irina's work and Irina's home. In fact, we know that the car takes 0.4 hourse traveling at 27 mph, so the distance covered should be

d=vt=(27 mph)(0.4 h)=10.8 mi

When Irina rides to work with her bike, she travels at a speed of 16 mph. So we can find the time she takes by dividing the total distance (10.8 miles) by her speed:

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Which statement about velocity is true?
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Velocity has both speed and direction. Speed is constant. ... Speed is measured over time.

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The properties of each state of a substance are due largely to the degree (amount) of intermolecular bonding. True False
marysya [2.9K]

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true

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6 0
2 years ago
Calculate the de Broglie wavelength of an electron accelerated from rest through a potential difference of (a) 100 V, (b) 1.0 kV
forsale [732]

Answer:

(a) \lambda=1.227\ A

(b) \lambda=0.388\ A

(c) \lambda=0.038\ A

Explanation:

Given that,

(a) An electron accelerated from rest through a potential difference of 100 V. The De Broglie wavelength in terms of potential difference is given by :

\lambda=\dfrac{h}{\sqrt{2meV} }

Where

m and e are the mass of and charge on an electron

On solving,

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

V = 100 V

\lambda=\dfrac{12.27}{\sqrt{100} }\ A

\lambda=1.227\ A

(b) V = 1 kV = 1000 V

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

\lambda=\dfrac{12.27}{\sqrt{1000} }\ A

\lambda=0.388\ A

(c) If V=100\ kV=10^5\ V

\lambda=\dfrac{12.27}{\sqrt{10^5} }\ A

\lambda=0.038\ A

Hence, this is the required solution.

7 0
2 years ago
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